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2 years ago

Can some plz help me?

Mathematics

1 answer:

Lesechka [4]2 years ago

5 0

Answer:

demos is the website

Step-by-step explanation:

listen i dont know what grade your in in school middle or high but there is this very beneficial website im gonna give you it is graphing we use it in my high school math class so basically you put i the coordinates and doing so its gonna graph it for you. all you have to do is type the equation on the side once done and graphed you click the dots zoom in and out also once you click the dot you answer should be with the number.

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John jogs 2 7/10 miles to the park. Marsha jogs 4/5 miles to the park. How much farther does John jog?

Elden [556K]

Answer:

1.9 miles.

Step-by-step explanation:

John jogs 2 7/10 miles to the park. Marsha jogs 4/5 miles to the park.

Convert the fractions into decimals:

2 7/10 = 2.7

4/5 = 0.8

Subtract '0.8' from '2.7':

$2.7-0.8=1.9$

John should jog 1.9 miles farther than Marsha.

Hope this helps.

7 0

3 years ago

Read 2 more answers

Xto the 2nd power - 49 = 0

AnnZ [28]

Answer:

7 to the second power... because 7 times is 49 and 49-49 is 0... so 7 to the second power

6 0

2 years ago

Help me out please <3

Fynjy0 [20]

Answer: you could do store A is $8 per hour, and thirteen $13 per day, store B can be $3 per hour, $18 per day

I'm not too confedent but I'm still happy to help!

8 0

2 years ago

Solve the following equations by factorisation method.Only factorisation not dharacharya.

Luba_88 [7]

Hello, please consider the following.

When $x_1$ and $x_2$ are two roots, we can factorise as

$ax^2+bx+c=a(x-x_1)(x-x_2)=a(x^2-(x_1+x_2)x+x_1x_2)=0$

So for the first equation, we can say that the sum of the zeros is

$\dfrac{a^2+b^2}{2}=\dfrac{a^2}{2}+\dfrac{b^2}{2}$

and the product is

$\dfrac{a^2b^2}{4}=\dfrac{a^2}{2}\dfrac{b^2}{2}$

So we can factorise as below.

$4x^2-2(a^2+b^2)x+a^2b^2=(2x-a^2)(2x-b^2)=0$

And the solutions are

$\boxed{\sf \n\bf \ \dfrac{a^2}{2} \ \ and \ \ \dfrac{b^2}{2}}$

For the second equation, we will complete the square and put the constant on the right side and take the root.

Let's do it!

$9x^2-9(a+b)x+2a^2+5ab+2b^2=0\\\\9(x-\dfrac{a+b}{2})^2-9\dfrac{(a+b)^2}{4}+2a^2+5ab+2b^2=0\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{9(a+b)^2-8a^2-20ab-8b^2}{4}\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{9a^2+18ab+9b^2-8a^2-20ab-8b^2}{4}\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{a^2+b^2-2ab}{4}=\dfrac{(a-b)^2}{4}\\\\(x-\dfrac{a+b}{2})^2=\dfrac{(a-b)^2}{2^2\cdot 3^2}$

We take the root, and we find the two solutions

$\begin{aligned}x_1&=\dfrac{a+b}{2}-\dfrac{a-b}{6}\\\\&=\dfrac{3a+3b-a+b}{6}\\\\&=\dfrac{2a+4b}{6}\\\\&\boxed{=\dfrac{a+2b}{3}}\end{aligned}$

$\begin{aligned}x_1&=\dfrac{a+b}{2}+\dfrac{a-b}{6}\\\\&=\dfrac{3a+3b+a-b}{6}\\\\&=\dfrac{4a+2b}{6}\\\\&\boxed{=\dfrac{2a+b}{3}}\end{aligned}$

Thank you.

6 0

2 years ago

Can someone please tell me what the mean median mode and range is for 92, 63, 22, 80, 63, 71, 44, 35 please?

Leto [7]

Mean- 58.75
median- 63
mode-63
range-70

6 0

2 years ago