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3 years ago

In APQR, p = 690 cm, a = 290 cm and r=450 cm. Find the measure of ZQ to the

Mathematics

1 answer:

katen-ka-za [31]3 years ago

3 0

9514 1404 393

Answer:

16.8°

Step-by-step explanation:

The Law of Cosines can be rearranged to give the angle measure.

angle Q = arccos((p² +r² -q²)/(2pr))

angle Q = arccos((690² +450² -290²)/(2×690×450))

angle Q = arccos(594500/621000) ≈ 16.7985°

The measure of angle Q is about 16.8°.

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One zero of the polynomial function f(x) = x3 − 9x2 + 20x is x = 0. What are the zeros of the polynomial function? 0, −5, −4 0,

jeyben [28]

Answer:

Step-by-step explanation:

As x = 0 is a zero, (x + 0) is a factor.

Dividing the equation by (x + 0) leaves x² - 9x + 20.

Factoring this polynomial

x² - 9x + 20 = (x - 4)(x - 5)

x - 4 = 0

x = 4

x - 5 = 0

x = 5

The zeros are at 0, 4, and 5.

Which can be verified by using a plotting calculator.

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2 years ago

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Simplify the expression in e^5

fredd [130]

Answer:

Step-by-step explanation:

ok im not sure if this is it but 148.41315910

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3 years ago

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5a – 10b = 45, when b = 3

balandron [24]

Well, since you have the value of b, the first thing you want to do is substitute that value in for b.

5a - 10(3) = 45

10*3 = 30

5a - 30 = 45

Now, to get the variable by itself (a) you have to + 30 because you have to reverse the subtraction.

5a = 75

Now, you divide by 5 to finish getting a by itself.

a = 15

Hope this helps!

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3 years ago

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Find the Value of x Please answer!! No links!!

statuscvo [17]

Answer:

x = 15 inches

Step-by-step explanation:

$a^{2} +b^{2} =c^{2} \\b^{2} = c^{2} - a^{2} \\b^{2} = (25 inches)^{2} - (40 inces/2)^{2} = \sqrt{225} = 15 inches$

4 0

3 years ago

X3(2x2 + 3x) a. 2x5 + 3x4 b. 5x9 c. 2x6 + 3x3 d. 5x

Serhud [2]

Answer:

$2x^5+3x^4$

Step-by-step explanation:

$x^3\left(2x^2+3x\right)$

Apply distributive law: $a\left(b+c\right)=ab+ac$

$x^3\left(2x^2+3x\right)=x^3\times \:2x^2+x^3\times \:3x$

$x^3\times \:2x^2+x^3\times \:3x$

$2x^5+3x^4$

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3 years ago