Sorry man, this isn’t really my cup of tea
Answer:
There are often not more than one or two independent variables tested in an experiment.
Answer:
44,55 can be produced.
Explanation:
First, we balanced the equation
1Cu + 2AgNO3 → 1Cu(NO3)2 + Ag
Then, we find the moles of each reagent


Now, we find the limiting reagent from the quantities of product that can be formed from each reagent


1,086 moles of AgNO3 is necessary for each mole of Cu since we have 0.413 moles of Ag(NO3), the nitrate is the limiting reagent
the value of the limiting reagent determines the amount of product that is generated
∴ 0,413 mol of Ag can be produced
Ag =
= 44,55g
Ag≈ 44,6g
B. Straining liquid out of food