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mars1129 [50]
3 years ago
7

What is the total distance covered if you walk 5 meters to the north 5 meter east 5 meters south

Chemistry
1 answer:
mihalych1998 [28]3 years ago
8 0

0! because you walked back in forth in diferent direcions

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The pH of a solution in which the concentration of H+ is 0.010M will be:
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B: 2

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2 years ago
Choose all of the answers that are correct when describing this atom.
gregori [183]
I believe that this atom is  chlorine and the atom has an overall charge of zero.
Chlorine is chemical element which is atomic number 17 in the periodic table. Each chlorine atom has 17 protons (positively charged) in the nucleus balanced by 17 electrons (negatively charged) in the energy shells ( thus an overall charge of zero) 
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3 years ago
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238,2U --&gt; 234Th +<br> 90
stiv31 [10]

Answer:

\\_{2}^{4} \alpha

Explanation:

In this question, we wish to find the missing nuclei for the equation:

\\_{92}^{238} U\rightarrow _{90}^{234} Th + _{Z}^{A} X

In order to find the missing species, we need to use the charge and mass balance law. That is, the mass should be conserved: the total mass on the left-hand side with respect to the arrow should be equal to the total mass on the right-hand side with respect to the arrow:

238 = 234 + A

Notice from here that:

A = 238 - 234 = 4

So far we know that the mass of X is 4. Similarly, we apply the law of charge conservation. The total charge should be conserved:

92=90+Z

From here:

Z = 92-90=2

We have a particle:

\\_{2}^{4} X

Looking at the periodic table, an atom with Z = 2 corresponds to helium. This can also be written as an alpha particle:

\\_{2}^{4} \alpha

5 0
2 years ago
How many grams are in 1.76 x 10^23 atoms of iodine
Mariana [72]

Answer:

\boxed {\boxed {\sf About \ 37.1 \ grams \ of \ iodine }}

Explanation:

To convert from atoms to grams, you must first convert atoms to moles, then moles to grams.

1. Convert Atoms to Moles

To convert atoms to grams, Avogadro's number must be used.

6.022*10^{23}

This number tells us the number of particles (atoms, molecules, ions, etc.) in 1 mole. In this case, the particles are atoms of iodine.

\frac{6.022*10^{23} \ atoms \ I  }{1 \ mol \ I}

Multiply the given number of atoms by Avogadro's number.

1.76*10^{23} \ atoms \ I*\frac{6.022*10^{23} \ atoms \ I  }{1 \ mol \ I}

Flip the fraction so the atoms of iodine will cancel out.

1.76*10^{23} \ atoms \ I*\frac{  1 \ mol \ I}{6.022*10^{23} \ atoms \ I}

1.76*10^{23}* \frac{1 \ mol \ I}{6.022*10^{23} }

Multiply so the problem condenses into 1 fraction.

\frac{1.76*10^{23} \ mol \ I}{6.022*10^{23} }

0.2922617071 \ mol \ I

2. Convert Moles to Grams

Now we must use the molar mass of iodine, which is found on the Periodic Table.

  • Iodine Molar Mass: 126.9045 g/mol

Use this mass as a fraction.

\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}

Multiply this fraction by the number of moles found above.

0.2922617071 \ mol \ I*\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}

Multiply. The moles of iodine will cancel.

0.2922617071 *\frac{ 126.9045 \ g\ I }{ 1 }

The 1 as a denominator is insignificant.

0.2922617071 *{ 126.9045 \ g\ I }

37.08932581 \ g \ I

3. Round

The original measurement of 1.76*10^23 has 3 significant figures (1, 7, and 6). Therefore we must round our answer to 3 sig figs. For this answer, that is the tenths place.

37.08932581 \ g \ I

The 8 in the hundredth place tells us to round the 0 up to a 1.

\approx 37.1\ g \ I

There is about <u>37.1 grams of iodine </u>in 1.76*10^23 atoms.

5 0
3 years ago
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