Question

Calculate the amount of heat energy, in kJ, needed to increase the temperature of 200g of water by 300 C.

Answer 1

Answer:

Q = 246 kJ

Explanation:

It is given that,

Mass of water, m = 200 g

Let initial temperature, $T_i=5^{\circ}$

Final temperature of water, $T_f=300^{\circ} C$

We know that the specific heat capacity of water, $c=4.18\ J/g-^{\circ} C$

So, the heat energy needed to raise the temperature is given by :

$Q=mc\Delta T\\\\Q=200\times 4.18\times (300-5)\\\\Q=246620\ J$

or

Q = 246 kJ

So, the heat energy of 246 kJ is needed.