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BigorU [14]
3 years ago
15

Calculate the amount of heat energy, in kJ, needed to increase the temperature of 200g of water by 300 C.

Chemistry
1 answer:
shtirl [24]3 years ago
8 0

Answer:

Q = 246 kJ

Explanation:

It is given that,

Mass of water, m = 200 g

Let initial temperature, T_i=5^{\circ}

Final temperature of water, T_f=300^{\circ} C

We know that the specific heat capacity of water, c=4.18\ J/g-^{\circ} C

So, the heat energy needed to raise the temperature is given by :

Q=mc\Delta T\\\\Q=200\times 4.18\times (300-5)\\\\Q=246620\ J

or

Q = 246 kJ

So, the heat energy of 246 kJ is needed.

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Cytokinesis happens differently for plant and animal cells. Both separate cytoplasm between two new daughter cells. However, whi
victus00 [196]

Answer:

animal cell

Explanation:

Cytokinesis -

It refers to the process of cell division, which takes place during mitosis, is known as cytokinesis.

The process of cytokinesis is different for animal cell and plant cell.

  • Where, in case of plant cell, a separation, known as cell plate is formed along the center of the parent cell, which is responsible for the separation of the cells.
  • Whereas, in case of animal cell, the plasma membrane contracts itself along the center, until the two daughter cells are separated from each other.

Hence, from the given information of the question,

The correct answer is animal cell.

7 0
3 years ago
Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
lara [203]

If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

learn more about base dissociation constant:

brainly.com/question/9234362

#SPJ4

7 0
1 year ago
If you stirred some sugar in water the sugar would disappear but the water would taste sweet. This is because __________ change
olganol [36]

a hopefully this is helpful

7 0
3 years ago
A cube has an edge length of 9 cm .
Angelina_Jolie [31]

Answer:

9^3 i think so like 279

Explanation:

blah

5 0
3 years ago
what would be the ph of an aqueous solution of sulphuric acid which is 5×10^_5 mol l^_1 in concentration​
guajiro [1.7K]

Answer:

the ph of an aqueous solution of sulphuric acid which is 5*10^5 mol in concentration is basic in nature

6 0
3 years ago
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