75.0 mL in liters:
75.0 / 1000 => 0.075 L
1 mole -------------------- 22.4 L ( at STP)
( moles Hg) ------------- 0.075 L
moles Hg = 0.075 x 1 / 22.4
moles = 0.075 / 22.4
= 0.00334 moles of Hg
Hg => 200.59 u
1 mole Hg ----------------- 200.59 g
<span>0.00334 moles Hg ----- ( mass Hg )
</span>
mass Hg = 200.59 x 0.00334 / 1
mass Hg = 0.6699 / 1
= 0.6699 g of Hg
Group 1 and group 7 of element group consists of alkali metal, which are generally combined with other elements in nature, so they have properties of compound
Answer:Option D
Explanation: Its Just the right answer :)
Answer:
Explanation:
Use the ideal gas equation:

Where:
- p is pressure: 0.950atm
- V is volume: unknown
- n is number of moles: unknown
- R is the universal constat of gases: 0.08206 atm.liter/ (K.mol)
- T is the absolute temperature: 345K
Use the <em>molar mass</em> of the gas to include the density in the formula:
- molar mass = mass in grams / number of moles
- ⇒ mass in grams = number of moles × molar mass
- density = mass in grams / volume
- ⇒ density = number of moles × molar mass / volume
- density = (n/V) × molar mass
- ⇒ n/V = density / molar mass
Clear n/V from the gas ideal equation and subsittute with density/molar mass:
- density / molar mass = n/V
- density/molar mass = p/(RT)
- molar mass = density × RT / p
Now you can subsitute the data:
molar mass = (3.50g/liter) × 0.08206 atm.liter/(K.mol) × 345K / 0.950 atm
- Round to the nearest whole number: 104g/mol ← answer