Question

The instruction booklet for your pressure cooker indicates that its highest setting is 11.8 psipsi . You know that standard atmospheric pressure is 14.7 psipsi, so the booklet must mean 11.8 psipsi above atmospheric pressure. At what temperature in degrees Celsius will your food cook in this pressure cooker set on "high"?

Answer 1

Answer: The temperature at which the food will cook is 219.14°C

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=14.7psi\\T_1=273K\\P_2=(14.7+11.8)psi=26.5psi\\T_2=?$

Putting values in above equation, we get:

$\frac{14.7psi}{273K}=\frac{26.5psi}{T_2}\\\\T_2=\frac{26.5\times 273}{14.7}=492.14K$

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

$T(K)=T(^oC)+273$

$492.14=T(^oC)+273\\\\T(^oC)=219.14^oC$

Hence, the temperature at which the food will cook is 219.14°C