<h3><u><em>Option B</em></u></h3><h3><u><em>The equation of a line, in point- slope form, that passes through (5, -3) and has a slope of 2/3</em></u></h3><h3><u><em /></u> $y + 3 = \frac{2}{3}(x -5)$ <u><em /></u></h3>

<em><u>Solution:</u></em>

<em><u>The equation of line in point slope form is given as:</u></em>

$y - y_1 = m(x-x_1)$

Where, "m" is the slope of line

Given that,

slope = 2/3

$m = \frac{2}{3}$

The line passes through (5, -3)

Substitute m = 2/3 and $(x_1, y_1)$ = (5, -3) in point slope form

$y - (-3) = \frac{2}{3}(x -5)\\\\y + 3 = \frac{2}{3}(x -5)$

Thus equation of line in point slope form is found

8 0

2 years ago

This is line segments

lianna [129]

Step-by-step explanation:

$here \: given \: that \: total \: lenth = bd = 67 \\ then \: bd = bc + cd \\ so \: we \: can \: write \: that \\ 67 = 3x - 2 + 4x + 13 \\67 = 3x + 4x - 2 + 13 \\ 67 = 7x + 11 \\ 7x = 67 - 11 \\ 7x = 56 \\ x = \frac{56}{7} \\ x = 8 \\ thankyou$