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irina1246 [14]
3 years ago
11

I need help I forgot how to this AND THANK YOU

Mathematics
2 answers:
zlopas [31]3 years ago
4 0

Answer:

x=-2

Step-by-step explanation:

same on both sides

JulsSmile [24]3 years ago
3 0
Answer: x=-2
Look at where the curve splits in the middle, that is where the line of symmetry is.
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Which of the folowing is equal to 7 1/3
Romashka-Z-Leto [24]

Answer:

22/3

Step-by-step explanation:

Make the whole number turn into a fraction, (21/3) and add the numerator (1/3), which the answer would be 22/3

7 0
3 years ago
A certain four​-cylinder combination lock has 50 numbers on it. to open​ it, you turn to a number on the first​ cylinder, then t
kumpel [21]

A certain four​-cylinder combination lock has 50 numbers on it.

It is a four cylinder combination lock

Each cylinder has 50 numbers

So we have to choose 4 numbers for 4 cylinders

_____ , ______ , ______, _____

you turn to a number on the first​ cylinder

We have 50 numbers so we have 50 combinations

__50___ , ______ , ______, _____

Repetitions are allowed so we do the same for remaining three

50 , 50 , 50 , 50

50 * 50 * 50* 50 = 6250000

There are 6250000 different lock combinations .

7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B125%20%7D%20-%20%5Csqrt%7B180%7D%20%2B%20%5Csqrt%7B45%7D%20" id="TexFormula1" tit
Kobotan [32]

Answer:

2\sqrt{5}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying the radicals

\sqrt{125} = \sqrt{25(5)} = \sqrt{25} × \sqrt{5} = 5\sqrt{5}

\sqrt{180} = \sqrt{36(5)} = \sqrt{36} × \sqrt{5} = 6\sqrt{5}

\sqrt{45} = \sqrt{9(5)} = \sqrt{9} × \sqrt{5} = 3\sqrt{5}

Thus

\sqrt{125} - \sqrt{180} +\sqrt{45}

= 5\sqrt{5} - 6\sqrt{5} + 3\sqrt{5}

= 2\sqrt{5}

3 0
3 years ago
Can someone please help me on this??
TEA [102]
X= base

Area= 1/2(base)(height)
24=1/2(b)(4)
24=(4*1*b)/2
24=4b/2
Divide 2 into 4
24=2b
Divide both sides by 2
12=b

base= x= 12 units

Hope this helps! :)

4 0
3 years ago
If a scalene triangle has its measures 4 m, 11 m and 8 m, find the largest angle.
soldier1979 [14.2K]

Answer:

129.8 approximately

Step-by-step explanation:

So this sounds like a problem for the Law of Cosines. The largest angle is always opposite the largest side in a triangle.

So 11 is the largest side so the angle opposite to it is what we are trying to find. Let's call that angle, X.

My math is case sensitive.

X is the angle opposite to the side x.

Law of cosines formula is:

x^2=a^2+b^2-2ab \cos(X)

So we are looking for X.

We know x=11, a=4, and b=8 (it didn't matter if you called b=4 and a=8).

11^2=4^2+8^2-2(4)(8)\cos(X)

121=16+64-64\cos(X)

121=80-64\cos(X)

Subtract 80 on both sides:

121-80=-64\cos(X)

41=-64\cos(X)

Divide both sides by -64:

\frac{41}{-64}=\cos(X)

Now do the inverse of cosine of both sides or just arccos( )

[these are same thing]

\arccos(\frac{-41}{64})=X

Time for the calculator:

X=129.8 approximately

3 0
3 years ago
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