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Ganezh [65]
2 years ago
7

Would I be right if I said 21pi/10 and -pi/10 are two angles coterminal with pi/10?

Mathematics
1 answer:
Anna71 [15]2 years ago
7 0
Two angles are coterminal if they differentiate in a factor of k*(2pi). This is  a multiple of 360 degrees.

In this case 21 [pi /10] = [pi / 10] + 20 [pi/10] = [pi/10] + 2pi, then 21pi/10 is coterminal with pi/10.

In the case of -pi/10 you cannot get to pi/10 by adding a multiple of 2pi , then they are not coternminals.

Conclusion: you would not be right.
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Two-thirds had their picture taken. If 124 had their picture taken, how many total?
Vesna [10]

Answer:

186

Step-by-step explanation:

1/3 would be 62. You get it by dividing 124 by 2.

Add the 62 onto 124

6 0
2 years ago
Which statements are correct regarding the properties of trapezoids?
natulia [17]

Answer:

The diagonals of an isosceles trapezoid are congruent.  

The bases of a trapezoid are parallel.

4 0
3 years ago
A wooden disk is shaped like a cylinder with a radius of 20.2 millimeters, and a height of 3.9 millimeters. What is the surface
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The Area is = 3058.78 pir^2
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3 years ago
To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data
nexus9112 [7]

Answer:

a) \sigma = 0.167

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of \mu. So X - \mu = 0.5 must have Z = 3 and X - \mu = -0.5 must have Z = -3.

So

Z = \frac{X - \mu}{\sigma}

3 = \frac{0.5}{\sigma}

3\sigma = 0.5

\sigma = \frac{0.5}{3}

\sigma = 0.167

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that \sigma = 2.8

The standard deviation of a sample of n young man is given by the following formula

s = \frac{\sigma}{\sqrt{n}}

We want to have s = 0.167

0.167 = \frac{2.8}{\sqrt{n}}

0.167\sqrt{n} = 2.8

\sqrt{n} = \frac{2.8}{0.167}

\sqrt{n} = 16.77

\sqrt{n}^{2} = 16.77^{2}

n = 281.23

We need a sample of at least 282 young men.

6 0
3 years ago
Help please I’m lost
zaharov [31]

Answer:

d

Step-by-step explanation:

f(3)=5(3)²-7(4(3)+3))

    =45-105

    = -60

8 0
2 years ago
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