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Ganezh [65]
3 years ago
7

Would I be right if I said 21pi/10 and -pi/10 are two angles coterminal with pi/10?

Mathematics
1 answer:
Anna71 [15]3 years ago
7 0
Two angles are coterminal if they differentiate in a factor of k*(2pi). This is  a multiple of 360 degrees.

In this case 21 [pi /10] = [pi / 10] + 20 [pi/10] = [pi/10] + 2pi, then 21pi/10 is coterminal with pi/10.

In the case of -pi/10 you cannot get to pi/10 by adding a multiple of 2pi , then they are not coternminals.

Conclusion: you would not be right.
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A weightlifter holds a 1,700 N barbell 1 meter above the ground. One end of a 2-meter-long chain hangs from the center of the ba
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3 years ago
Mr. Sims received $3.36 in change from his grocery purchase. If the total amount of his purchase was $56.64, which equation and
polet [3.4K]

Answer:

The answer to your question is x – 56.64 = 3.36; x = 60  because He gave the cashier 60 dollars, and the cashier game him back 3.36 dollars. And 60-$56.64 = $3.36.

Step-by-step explanation:

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3 years ago
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Really confused on what to do, please help!
jenyasd209 [6]

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5 0
3 years ago
Bobby knows that the perimeter of the original rectangle is 120 meters. He also knows that the perimeter of the reduced rectangl
Whitepunk [10]

Answer:

<u>24 meters</u> is the width of the original rectangle.

Step-by-step explanation:

Given:

Bobby knows that the perimeter of the original rectangle is 120 meters. He also knows that the perimeter of the reduced rectangle is 30 meters and the reduced rectangle has a length of 9 meters.

Now, to get the width of original rectangle.

The reduced rectangle's perimeter = 30 meters.

The reduced rectangle's length = 9 meters.

Now, we find the width of reduced rectangle by using formula:

Let the width of reduced rectangle be x.

Perimeter=2\times length+2\times width

30=2\times 9+2\times x

30=18+2x

<em>Subtracting both sides by 18 we get:</em>

<em />12=2x<em />

<em>Dividing both sides by 2 we get:</em>

6=x\\\\x=6\ meters.

The width of reduced rectangle = 6 meters.

Now, to get the width of original rectangle:

Let the width of original rectangle be w.

<em>As given, the perimeter of the original rectangle = 120 meters.</em>

<em>And, the perimeter of reduced rectangle is 30 meters and its width is 6 meters.</em>

<em>So, 30 is equivalent to 6.</em>

<em>Thus, 120 is equivalent to </em>w.<em />

Now, to get the width using cross multiplication method:

\frac{30}{6}=\frac{120}{w}

<em>By cross multiplying we get:</em>

<em />30w=720<em />

<em>Dividing both sides by 30 we get:</em>

<em />w=24\ meters.<em />

<em>The width of original rectangle = 24 meters.</em>

Therefore, 24 meters is the width of the original rectangle.

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3 years ago
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