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Katarina [22]
3 years ago
12

The amount of 217 mg of an isotope is given by A(t) = 217 € -0.0171, where t is time in years since the initial amount of 217 mg

was present. Find the amount to the nearest milligraM left after 20 years
Chemistry
2 answers:
professor190 [17]3 years ago
8 0

Answer:

The amount left after 20 years = 154.15 mg

Explanation:

Maru [420]3 years ago
4 0

The amount left after 20 years = 154.15 mg

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually radioactive elements have an unstable atomic nucleus.  

The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles  

The decay formula for isotope :

\tt \large{\boxed{\bold{A(t)=217e^{-0.0171t}}}

Then for t=20 years, the amount left :

\tt A(t)=217e^{-0.0171\times 20}\\\\A(t)=154.15~mg

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Answer:

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1. Fill the matchbox with pebbles. Weigh the matchbox with the pebbles inside. Record that weight.

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3. Tie the other end of the string to a corner of the plastic bag, leaving an opening to put in coins.

4. Add coins one by one until the box is pulled off the table.

5. Count and record the number of coins and the weight of the bag with the coins in it.

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Explanation:

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5 0
3 years ago
Suppose 0.09886 M KOH is titrated into 15.00 mL H2SO4 of unknown concentration until the equivalence point is reached. It takes
AleksAgata [21]

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Explanation:

8 1
3 years ago
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Answer:

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6 0
3 years ago
CH4(g)+O2(g)→CO2(g)+H2O(g). What mass of water is produced from the complete combustion of 5.00×10−3 g of methane?
bixtya [17]

Answer:

1gram of water

Explanation:

First balance the equation

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500×10-3what about 2?

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3 years ago
How many moles of NO2 are present in 138.01 g
Sophie [7]

Answer:

3.0002 moles

Explanation:

Data Given:

mass of NO₂ = 138.01 g

No. of moles NO₂ = ?

Solution

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          no. of mole = mass in grams / molar mass

Molar mass of NO₂ = 14 + 2(16)

Molar mass of NO₂ = 14 + 32 = 46 g/mol

Put values in above equation

               no. of mole = 138.01 g / 46 g/mol

               no. of mole = 3.0002 moles

no. of mole of NO₂ = 3.0002 moles

8 0
3 years ago
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