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nirvana33 [79]
3 years ago
14

3 examples of substance that are soluble in water?

Chemistry
2 answers:
sp2606 [1]3 years ago
8 0

Answer:

salt, rocks, blah

Explanation:

JulsSmile [24]3 years ago
4 0

Answer:

<h2><u><em>We call substances that dissolve in water soluble. Sugar and salt are examples of soluble substances. </em></u></h2><h2><u><em>You'll need </em></u></h2><h2><u><em>Transparent containers – test tubes or beakers. </em></u></h2><h2><u><em>Water ( warm and cold ) </em></u></h2><h2><u><em>Substances to try to dissolve eg. sugar, coffee, pepper, sand, flour, salt.</em></u></h2>

Explanation:

<h2><u><em>Hope this helps </em></u></h2>
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What is SO2 shape name?
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Answer:Molecular Formula SO2

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5 0
3 years ago
Based on table N of the reference tables what is the number of hours required for 42k (potassium -42) to undergo three half-life
skelet666 [1.2K]

The number of hours required : 37.2 hours

<h3>Further explanation</h3>

Given

⁴²K (potassium -42)

Required

The number of hours

Solution

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually, radioactive elements have an unstable atomic nucleus.  

Based on Table N(attached), the half-life for ⁴²K is 12.4 hours, which means half of a sample of ⁴²K will decay in 12.4 hours

For three half-life periods :

\tt 3\times 12.4=37.2~hours

3 0
3 years ago
What of the following is NOT a common property of metals?
Yuri [45]

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5 0
3 years ago
A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. Calculate the pressure when the volume is 1.41 L and the
Vlad1618 [11]

A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

<h3>What is Combined Gas Law ?</h3>

This law combined the three gas laws that is (i) Charle's Law (ii) Gay-Lussac's Law and (iii) Boyle's law.

It is expressed as

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where,

P₁ = first pressure

P₂ = second pressure

V₁ = first volume

V₂ = second volume

T₁ = first temperature

T₂ = second temperature

Now put the values in above expression we get

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

\frac{1.02\ atm \times 2.30\ L}{281\ K} = \frac{P_2 \times 1.41\ L}{298\ K}

P_{2} = \frac{1.02\ atm \times 2.30\ L \times 298\ K}{281\ K \times 1.41\ L}

P₂ = 1.76 atm

Thus from the above conclusion we can say that A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

Learn more about the Combined gas Law here: brainly.com/question/13538773

#SPJ4

4 0
2 years ago
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