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3 years ago

My picture is my question

Mathematics

1 answer:

zvonat [6]3 years ago

7 0

Answer:

Step-by-step explanation:

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Write an equation in slope intercept form of the line passing through (5,-4) and is perpendicular to a line whose equation is -2

Sergeu [11.5K]

Rearrange the given equation in slope intercept form
$y = \frac{3x - 1}{ - 2} \\ y = - \frac{3}{2} x + \frac{1}{2}$
slope of the required line is
$- \frac{1}{ - \frac{3}{2} } = \frac{2}{3}$
equation is given by
$y - y1 = m(x - x1) \\ y - - 4 = \frac{2}{3} (x - 5) \\ y + 4 = \frac{2x}{3} - \frac{10}{3} \\ y = \frac{2x}{3} - \frac{10}{3} - 4 \\ y = \frac{2}{3} x - \frac{22}{3}$

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3 years ago

Which ordered pair is a solution of the equation y equals x minus 3

Rom4ik [11]

Y = x-3

Basically you just need to plug in an x value and solve for y
y = x - 3
y = (4) - 3
y = 1

In this case, the ordered pair of this equation would be (4, 1)

You can do this given any x or y coordinate

Hope this helps

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3 years ago

What are the zeros of the function defined by the polynomial<br> x2 + 7x+12?

ryzh [129]

Answer:

x = -4 and -3

Step-by-step explanation:

factors to (x+4)(x+3)

to zero them is -4 and -3

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2 years ago

A lottery game has balls numbered 1 through 21. What is the probability of selecting an even numbered ball or an 8? Round to nea

Viktor [21]

Answer: 0.476

Step-by-step explanation:

Let A = Event of choosing an even number ball.

B = Event of choosing an 8 .

Given, A lottery game has balls numbered 1 through 21.

Sample space: S= {1,2,3,4,5,6,7,8,...., 21}

n(S) = 21

Then, A= {2,4,6,8, 10,...(20)}

i.e. n(A)= 10

B= {8}

n(B) = 1

A∪B = {2,4,6,8, 10,...(20)} = A

n(A∪B)=10

Now, the probability of selecting an even numbered ball or an 8 is

$P(A\cup B)=\dfrac{n(A\cup B)}{n(S)}$

$=\dfrac{10}{21}\approx0.476$

Hence, the required probability =0.476

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3 years ago

Three points are colinear.<br> always<br> sometimes <br> never

Novosadov [1.4K]

Three or more points are collinear, if slope of any two pairs of points is same. With three points A, B and C, three pairs of points can be formed, they are: AB, BC and AC. If Slope of AB = slope of BC = slope of AC, then A, B and C are collinear points

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3 years ago

My picture is my question ​

My picture is my question