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3 years ago

Why does photosynthesis require 6 molecules of carbon dioxide and 6 molecules of water to make 1 molecule of glucose

1 answer:

6 0

For each molecule of glucose produced: 6 water water molecules are oxidized, and come to be the supply of electrons for carbon dioxide reduction. 6 molecules of carbon dioxide are required, one for every carbon atom in glucose. 6 molecules of oxygen are produced as a with the aid of made from water oxidation.

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3. The picture below is an example of a _________ _________. (Answer is 2 words)

Jlenok [28]

Answer:

I can't see any picture?????

8 0

3 years ago

In cars, ethylene glycol, C2H6O2, is used as a coolant and antifreeze. A mechanic fills a radiator with 7.1 kg of ethylene glyco

WITCHER [35]

Based on the given molecular formula, the molar mass of ethylene glycol is 62 g/mol. We solve for the number of moles of the solute,
n = (7.1 kg)(1000 g/ 1 kg) / 62g/mol = 114.52 mol
Then, we divide this value by the given mass of the water in kg
m = (114.52 mol) / 1.2 kg = 95.43 m
Thus, the molality of the substance is approximately equal to 95.43 m.

5 0

3 years ago

Read 2 more answers

Calcium carbonate decomposes to form calcium oxide and carbon dioxide, like this:

Leni [432]

Answer: The value of the equilibrium constant Kc for this reaction is 0.088

Explanation:

$Molarity=\frac{x}{M\times V_s}$

where,

x = given mass

M = molar mass

$V_s$ = volume of solution in L

Equilibrium concentration of $CaCO_3$ = $\frac{25.3}{100\times 9.0}=0.028M$

Equilibrium concentration of $CaO$ = $\frac{14.9}{56\times 9.0}=0.029M$

Equilibrium concentration of $CO_2$ = $\frac{33.7}{44\times 9.0}=0.085M$

The given balanced equilibrium reaction is,

$CaCO_3(s)\rightleftharpoons CaO(s)+CO_2(g)$

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CaO]\times [CO_2]}{[CaCO_3]}$

Now put all the given values in this expression, we get :

$K_c=\frac{0.029\times 0.085}{0.028}=0.088$

7 0

3 years ago

20 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Amanda [17]

The KE can be solve using the formula:
ke = 0.5 mv^2
where m is the mass of the object
v is the velocity
ke = 0.5 ( 2 kg ) ( 5 m/s)^2
ke = 25 J

the GPE can be solved using the formula:
GPE = mgh
where m is the mass
g is the acceleration due to gravity ( 9.81 m/s^2)
h is the height

GPE = ( 4 kg)(9.81 m/s^2)( 40 m)
GPE = 392.4 J

4 0

3 years ago

HOLMIUM

Sophie [7]

Answer:

1. The graph where x axis and y axis are present is called coordinate.

4. 18

8 0

3 years ago