"C6H12O6 and HC2H3O2" is the one pair among the following choices given in the question in which both <span>compounds have the same empirical formula. The correct option among all the options that are given in the question is the fourth option or option "D". I hope the answer has come to your great help.</span>
"A" is the answer. The chemical reaction is when the batter becomes brown.
B is mixing C is mass becoming a liquid and D. is dissolving no chemical reaction happened there.
Hope that helps!
Answer:
using higher concentration of the nucleophile
Explanation:
In SN2 reaction, the attack of the nucleophile on the substrate occurs simultaneously as the leaving group departs. The entering group normally attacks through the back side of the molecule. The reaction is concerted and bimolecular. This implies that the concentration of the nucleophile is important in the rate equation for the reaction. Hence increasing the concentration of the nucleophile will increase the rate of SN2 reaction.
Answer:
2H₂ + O₂ → 2H₂O.
Explanation:
- For the reaction of water formation:
<em>2H₂ + O₂ → 2H₂O.</em>
- It should apply the the law of conservation of mass that the no. of reactants atoms is equal to the no. of products atoms.
<em>So, every </em><em>2.0 moles of H₂ </em><em>react with </em><em>1.0 mole of O₂</em><em> to produce </em><em>2.0 moles of H₂O.</em>
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Answer:
- Nitrogen has four pairs of electrons: 3 bonds and 1 lone pair in the valence shell;
- Electrons repel one another based on the VSEPR theory;
- Nitrogen has a total of 7 protons (its atomic number is 7) in its nucleus.
Explanation:
The shape and the bond orientation of molecules and ions are both explained by the valences shell electron pair repulsion theory (VSEPR).
Ammonia, 
, is a molecule which contains three N-H bonds, as well as one lone pair on nitrogen. According to the VSEPR theory, molecules try to acquire a shape which would minimize the repulsion exhibited by the electron clouds present, that is, between the bonding (shared in a bond) and non-bonding (lone pair) electrons.
In VSEPR, our main step is to calculate the steric number, this is the sum of the number of bonds (ignoring the multiplicity of any bond) and the lone pairs on a central atom. In ammonia, we have 3 bonds and 1 lone pair, totaling to a steric number of 4. A steric number of 4 without any lone pairs on a central atom and just bonds would yield a tetrahedral shape with bond angles of 
.
Now, in this case, since we have a lone pair instead of a bond, it is repelling stronger decreasing the bond angles to about 
.
The greater the number of lone pairs, the lower the angle becomes.
To summarize:
- Nitrogen has four pairs of electrons: 3 bonds and 1 lone pair in the valence shell;
- Electrons repel one another based on the VSEPR theory;
- Nitrogen has a total of 7 protons (its atomic number is 7) in its nucleus.
