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bagirrra123 [75]
3 years ago
15

What is the wavelength of spectral line resulted from the electron transition from n=3 to n=2 in a hydrogen atom.

Chemistry
1 answer:
MakcuM [25]3 years ago
5 0

Answer:

\lambda=6.56x10^{-7}m

Explanation:

Hello there!

In this case, it possible to use the Rydberg equation in order to calculate the wavelength for this transition from n=3 to n=2 as shown below:

\frac{1}{\lambda} =R_H(\frac{1}{n_f^2}-\frac{1}{n_i^2} )

Thus, we plug in the corresponding energy levels and the Rydberg constant to obtain:

\frac{1}{\lambda} =10973731.6m^{-1}(\frac{1}{2^2}-\frac{1}{3^2} )\\\\\frac{1}{\lambda} =1524129.4m^{-1}\\\\\lambda=\frac{1}{1524129.4m^{-1}} \\\\\lambda=6.56x10^{-7}m

Best regards!

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Veseljchak [2.6K]

Answer:

2.29 moles of Cr₂O₃ are produced

Explanation:

This is the reaction:

4 Cr + 3O₂ → 2Cr₂O₃

Ratio for this equation is 4:2, so 4 moles of chromium can produce the half of moles of chromium(III) oxide

4.58 mol of Cr may produce (4.58  .2)/4 = 2.29 moles of Cr₂O₃

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3 years ago
How many moles are in 288.6 grams of titanium? Round your answer to the nearest hundredth. Be sure to include units.
Shtirlitz [24]

Answer:

Raw:

Namber of mole =mass/molar mass

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2 years ago
A sample of He gas (3.0 L) at 5.6 atm and 25°C was combined with 4.5 L of Ne gas at 3.6 atm and 25°C at constant temperature in
In-s [12.5K]

Answer:

3.6667

Explanation:

<u>For helium gas:</u>

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 3.0 L

V₂ = 9.0 L

P₁ = 5.6 atm

P₂ = ?

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{5.6}\times {3.0}={P_2}\times {9.0} atm

{P_2}=\frac {{5.6}\times {3.0}}{9.0} atm

{P_1}=1.8667\ atm

<u>The pressure exerted by the helium gas in 9.0 L flask is 1.8667 atm</u>

<u>For Neon gas:</u>

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 4.5 L

V₂ = 9.0 L

P₁ = 3.6 atm

P₂ = ?

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{3.6}\times {4.5}={P_2}\times {9.0} atm

{P_2}=\frac {{3.6}\times {4.5}}{9.0} atm

{P_1}=1.8\ atm

<u>The pressure exerted by the neon gas in 9.0 L flask is 1.8 atm</u>

<u>Thus total pressure = 1.8667 + 1.8 atm = 3.6667 atm.</u>

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