D(y) is a linear function. Linear function's domain are all real numbers
Answer:
I dont think so because a right triangle should have a 90 degree
we have

we know that

so

two solutions
<u>first solution </u>


the first solution is the interval---------> (-1,∞)
<u>second solution</u>




the second solution is the interval---------> (-∞,-1)
therefore
the solution is all real numbers except the number 
the answer in the attached figure
Answer:
As n tends to positive infinity, we have that,
A. 5/n + n/5 ---- converges
B. 5^-n. -----------converges
C. Sin n/5n------ converges
D. 5n + 5/n ------diverges
Step-by-step explanation:
Answer:
∠?=40°
Step-by-step explanation:
Remember that in a line AND a triangle there are <u>180 degree</u>s.
You correctly found the third angle in the left triangle to be 69°, Now plug it into the equation for a line, including 71°:
<u>69°+71°+x=180°</u>
1) Combine the degrees:
140°+x=180°
2) Subtract 140° from both sides:
x=40°
We have now found the bottom left angle for the triangle on the right to be 40°
To find the angle labeled "?" You must plug in all of the known angles of the triangle to be equal to 180°:
40°+100°+x=180°
1) Combine the degrees:
140°+x=180°
2) Subtract 140 from both sides:
∠?=40°