Exam help !!

Help plzz i will give you brianliest Which best describes the graph of the function f(x) = 3(1.8)^x A) The graph passes through

DanielleElmas [232]

Answer:

Step-by-step explanation:

Start with why C isn't the answer.

y = 1.8^0 . The power is zero. Anything to the zero power (anything except 0 to the 0 power) is 1. So 1.8^0 is 1 not something else. C assumes that somehow 0,1.8 turns into 1.8. It does not. The second part is also wrong but you don't need it. However here it is.

x = 0 y = 3

x = 1 y = 3 * 1.8 = 5.4

x = 2 y = 3 * 1.8^2 = 3*3.24 = 9.72

You should be able to see that if you multiply 5.4 by 3, you don't get 9.72

C just does not work.

=======

The actual answer is A. That's exactly what the graph does. If you multiply 5.4 * 1.8 you should get 9.72. Just for completeness, I've included the graph.

6 0

3 years ago

1. Write the following degrees in radian measure

ale4655 [162]

I’m on the same question sis ♥️

5 0

3 years ago

The given line passes through the points (-4,-3) and (4,

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

first we gotta find the slope of the first line

(-4,-3),(4,1)

slope = (y2 - y1) / (x2 - x1) = (1- (-3) / (4 - (-4) = (1 + 3) / (4 + 4) = 4/8 = 1/2

so the slope is 1/2.....so we are looking for a line that is perpendicular....perpendicular lines have negative reciprocal slopes...all that means is flip the slope and change the sign....so the slope we need is :

1/2....flip it....2/1.....change the sign....-2.....we need a -2 slope

y - y1 = m(x - x1)

slope = -2

(-4,3)...x1 = -4 and y1 = 3

now sub

y - 3 = -2(x - (-4) =

y - 3 = -2(x + 4) <=====

6 0

3 years ago

Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:

professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is $\{1,2,3,4\}$ .

a) We need to find a relation R reflexive and transitive that contain the relation $R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}$

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

1R4 and 4R1, then 1 must be related with itself.
4R1 and 1R4, then 4 must be related with itself.
4R1 and 1R2, then 4 must be related with 2.

Therefore $\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\}$ is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

since 1R2, then 2 must be related with 1.
since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

1R2 and 2R1, then 1 must be related with itself.
4R1 and 1R4, then 4 must be related with itself.
2R1 and 1R4, then 2 must be related with 4.
4R1 and 1R2, then 4 must be related with 2.
2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

$\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}$

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

1 must be related with 1,

2 must be related with 2,

3 must be related with 3,

4 must be related with 4

For be symmetric

since 1R2, 2 must be related with 1,
since 1R4, 4 must be related with 1.

For be transitive

Since 4R1 and 1R2, 4 must be related with 2,
since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

$\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}$

5 0

2 years ago

What is greater 1/3 or 1/8

Ludmilka [50]

1/3 is greater. Picture a pie with nothing cut into it. Then, you cut 3 equal pieces out of it, leaving no pie remaining. So, if you take 1 piece, you have 2 pieces that you didn't take. So if you do the exact same thing, but you cut <em>8 </em>pieces out of the pie and you take 1 piece, there are still 7 pieces remaining. So 1/8 is a smaller part of the pie than the 1/3, since you are cutting the pie into 8 identical pieces while with 1/3 you are cutting the same sized pie into 3 pieces. Sorry if I was confusing, just ask me if you want an easier-to-understand explanation. Also, if you pick a "brainliest" answer, it actually <em>gives </em>you points.

8 0

3 years ago

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