Given:
μ = 197.5 cm, the population mean
σ = 7.98 cm, the population standard deviation
Part a.
For the random variable x = 207.50 cm, the z-score is
z = (x-μ)/σ = (207.5-197.5)/7.98 = 1.253
From standard tables, obtain
P(x < 207.5) = 0.895
Answer: 0.895
Part b.
n = 20, the sample size
σ/√n = 7.98/√(20) = 1.7844
The random variable is x = 196.0 cm
The z-score is
z = (x-μ)/(σ/√n) = (196 - 197.5)/1.7844 = -0.8406
From standard tables, obtain
P(x < 196) = 0.2003
Answer: 0.2003
Part c.
In part b, the sample size of 30 is less than the minimum recommended value of 30.
The reasons why the normal distribution can be used are
(i) the z-score takes the sample size into account because σ is replaced by
σ/√n.
(ii) according to the Central Limit Theorem, sample means are normally
distributed.
Answer:
make it into y=mx+b form
Step-by-step explanation:
Answer:
100
Step-by-step explanation:
an isosceles triangle is equal so if one side is 100 degrees, the other side is too
