<span>To do these you will be adding or subtracting 2pi (or integer multiples of .
Since the given angles are in fraction form, it will help to have 2pi in fraction form, 2pi=10/5=6pi/3=4pi/2=18pi/9 NOTE: this>(/) stands for over like 1 over 2 EX. 1/2
too, so the addition/subtraction is easier.
Hint: When deciding if you have a number between 0 and 2pi, compare it to the fraction version of 2pi that you've been adding/subtracting.
For 17pi/5...
First we can see that 17pi/5 is more than 10pi/5 (aka 2pi). So we need to start subtracting: 17pi/5 - 10pi/5 = 7pi/5
Now we have a number between 0 and 10pi/5. So 7pi/5 is the co-terminal angle between 0 and 2pi.
I'll leave the others for you to do. Just remember that you might have to add or subtract multiple times before you get a number between 0 and 2pi.
P.S don't add or subtract at all if the number starts out between 0 and 2pi.</span>
What do you need help with?
In this question, both tickets cost 2$ per ticket.
The answer to this question would be: $0
In WinOne scenario, you need to match a ticket that has to pick from A-J(10 possibilities) and 0-9 (10 possibilities). The chance to win would be: 1/10* 1/10= 1/100
The expected value must be:
E= chance to win * win amount - ticket price
E= 1//100*$200 - $2= $2-$2= 0
Okay so john ran the diameter on the park
emily ran the circumference
πd = the circumference
therefore emily ran further
