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3 years ago

13

Please help me this is due today WORTH 40pts

1 answer:

Softa [21]3 years ago

5 0

Answer:

This number "four" is the maximum possible number of positive zeroes (that is, all the positive x-intercepts) for the polynomial f (x) = x 5 – x 4 + 3x 3 + 9x 2 – x + 5. Affiliate However, some of the roots may be generated by the Quadratic Formula , and these pairs of roots may be complex and thus not graphable as x -intercepts.

can calculate and graph the roots (x-intercepts), signs, Local Maxima and Minima, Increasing and Decreasing Intervals, Points of Inflection and Concave Up/Down intervals.

Step-by-step explanation:

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A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of

Gwar [14]

$\bold{\huge{\underline{ Solution}}}$

<h3><u>Given </u><u>:</u><u>-</u></h3>

A marker in the center of the fairway is 150 yards away from the centre of the green
While standing on the marker and facing the green, the golfer turns 100° towards his ball
Then he peces off 30 yards to his ball

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>distance </u><u>between </u><u>the </u><u>golf </u><u>ball </u><u>and </u><u>the </u><u>center </u><u>of </u><u>the </u><u>green </u><u>.</u>

<h3><u>Let's </u><u> </u><u>Begin </u><u>:</u><u>-</u></h3>

Let assume that the distance between the golf ball and central of green is x

<u>Here</u><u>, </u>

Distance between marker and centre of green is 150 yards
<u>That </u><u>is</u><u>, </u>Height = 150 yards
For facing the green , The golfer turns 100° towards his ball
<u>That </u><u>is</u><u>, </u>Angle = 100°
The golfer peces off 30 yards to his ball
<u>That </u><u>is</u><u>, </u>Base = 30 yards

<u>According </u><u>to </u><u>the </u><u>law </u><u>of </u><u>cosine </u><u>:</u><u>-</u>

$\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}$

Here, a = perpendicular height
b = base
c = hypotenuse
cos theta = Angle of cosine

<u>So</u><u>, </u><u> </u><u>For </u><u>Hypotenuse </u><u>law </u><u>of </u><u>cosine </u><u>will </u><u>be </u><u>:</u><u>-</u>

$\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}$

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

$\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}$

$\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}$

$\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}$

$\sf{ x^{2} = 22500 + 900 + 156.6}$

$\sf{ x^{2} = 23556.6}$

$\bold{ x = 153.48\: yards }$

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

5 0

2 years ago

Fill in the missing terms for the geometric sequence

expeople1 [14]

Step-by-step explanation:

<em>1</em><em>1</em><em>/</em><em>2</em><em>,</em><em> </em>-11, 22, <em>-</em><em>4</em><em>4</em><em>,</em><em> </em>88, -176

common ratio : 22/(-11) = -2

4 0

3 years ago

Please help me with this, corresponding parts

poizon [28]

Answer:

∠ C = 58°

Step-by-step explanation:

DB is a perpendicular bisector , so

∠ ADC = 2 × 32° = 64°

Since AD = CD then Δ ACD is isosceles with the base angle congruent , then

∠ C = $\frac{180-64}{2}$ = $\frac{116}{2}$ = 58°

4 0

3 years ago

On Tuesday morning, the temperature is -5º F. The temperature rises 3 4 degree each hour for 6 hours before dropping 1 4 degree

Mice21 [21]

Answer:

The temperature in degrees after 9 hours is -1.25 degrees Fahrenheit

Step-by-step explanation:

Here, we want to know the temperature after 9 hours

Per hour rise each hour is 3/4 degree = 0.75 degree

In 6 hours that will be 0.75 * 6 = 4.5 degrees

Or hour drop is 1/4 = 0.25 degree

In 3 hours, that will be 0.25 * 3 = 0.75 degree

Since it is a drop, we have -0.75 degree

Temperature after 9 hours will be;

-5 + 4.5 -0.75

= -5.75 + 4.5 = -1.25 degrees fahrenheit

8 0

3 years ago

Which formula represents this sequence

marysya [2.9K]

Answer:

pretty sure its b

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers