Find the area of the polygon. 32 m 20 m 16 m 40 m he area of the polygon is square meters.

How many liters of 60% alcohol solution should be added to 40 liters of a 20% alcohol solution to make a 50% solution?

kolbaska11 [484]

Answer:

120 liters of 60% alcohol solution is needed

Step-by-step explanation:

Let's assume

x liters of 60% alcohol solution is added

so, we get solution as

$=\frac{60}{100}\times x$

$=0.6x$

we are given

40 liters of a 20% alcohol solution is

$=40\times\frac{20}{100}$

$=8$

so, total alcohol solution is

$=8+0.6x$

now, we can find total solutions

total solutions is

$=x+40$

now, it is making 50% solution

so, we get

$\frac{8+0.6x}{x+40} =\frac{50}{100}$

now, we can solve for x

$\left(8+0.6x\right)\cdot \:100=\left(x+40\right)\cdot \:50$

$800+60x=50x+2000$

$10x=1200$

$x=120$

So,

120 liters of 60% alcohol solution is needed

4 0

3 years ago

a quart of paint covers 80 square feet. how many quarts should you buy to paint the ramp with two coats(Assume you will not pain

Evgesh-ka [11]

The answer would be 160 because 80+80=160

5 0

3 years ago

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13. To rent a car, you pay a one-time charge of $45 plus a charge of $0.29 for

deff fn [24]

Answer:

<em>The correct choice is (c) $79.80</em>

Step-by-step explanation:

The total charge for renting a car can be split into two parts:

A fixed one-time charge of $45

A variable charge of $0.29 per driven mile.

If I drive 120 miles, the variable charge will be 120*0.29 = $34.80

The total charge will be $45 + $34.80 = $79.80

The correct choice is (c) $79.80

7 0

3 years ago

PLS HELP ME!!! The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of

Pachacha [2.7K]

Hello!

The figure is made up of a cone and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box. cm³

Data: (Cone)

h (height) = 12 cm

r (radius) = 4 cm (The diameter is 8 being twice the radius)

Adopting: $\pi \approx 3.14$

V (volume) = ?

Solving: (Cone volume)

$V = \dfrac{ \pi *r^2*h}{3}$

$V = \dfrac{ 3.14 *4^2*\diagup\!\!\!\!\!12^4}{\diagup\!\!\!\!3}$

$V = 3.14*16*4$

$\boxed{V = 200.96\:cm^3}$

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 4 cm

Adopting: $\pi \approx 3.14$

If: We know that the volume of a sphere is $V = 4* \pi * \dfrac{r^3}{3}$ , but we have a hemisphere, so the formula will be half the volume of the hemisphere $V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}$

Formula: (Volume of the hemisphere)

$V = 2* \pi * \dfrac{r^3}{3}$

Solving:

$V = 2* \pi * \dfrac{r^3}{3}$

$V = 2*3.14 * \dfrac{4^3}{3}$

$V = 2*3.14 * \dfrac{64}{3}$

$V = \dfrac{401.92}{3}$

$\boxed{ V_{hemisphere} \approx 133.97\:cm^3}$

What is the approximate volume of this figure?

Now, to find the total volume of the figure, add the values: (cone volume + hemisphere volume)

Volume of the figure = cone volume + hemisphere volume

Volume of the figure = 200.96 cm³ + 133.97 cm³

$\boxed{\boxed{\boxed{V = 334.93\:cm^3 \to Volume\:of\:the\:figure \approx 335\:cm^3 }}}\end{array}}\qquad\quad\checkmark$

Answer:

The volume of the figure is approximately 335 cm³

_______________________

I Hope this helps, greetings ... Dexteright02! =)

8 0

3 years ago

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If you took a true “if then” statement and instead a not in each clause the new statement would also be true

Strike441 [17]

Answer:

True

Step-by-step explanation:

If it snows today, I will have to go out and clean the driveway.
If it does not snow today, I will not have to out and clean the driveway.
Without going into p's and q's and true false tables, I believe the negation is also true.

4 0

2 years ago

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Find the area of the polygon. 32 m 20 m 16 m 40 m he area of the polygon is square meters.​

Find the area of the polygon. 32 m 20 m 16 m 40 m he area of the polygon is square meters.