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yulyashka [42]
2 years ago
10

What is the average rate of change CAN SOMEONE PLEASE ANSWER THIS QUESTION I WILL BRAINLIEST

Mathematics
1 answer:
Andre45 [30]2 years ago
3 0
<h3>Answer: The average rate of change for both is -2</h3>

=======================================================

Explanation:

The x interval [0,3] is the same as writing 0 \le x \le 3

It starts at x = 0 and ends at x = 3.

The graph shows that x = 0 leads to y = 3. So we have the point (0,3) on the parabola. We also have the point (3,-3) on the parabola.

Let's find the slope of the line through these endpoints.

(x_1,y_1) = (0,3) \text{ and } (x_2,y_2)  = (3,-3)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{-3 - 3}{3 - 0}\\\\m = \frac{-6}{3}\\\\m = -2\\\\

The slope is -2. This is the average rate of change from x = 0 to x = 3.

This is because:

slope = rise/run = (change in y)/(change in x) = average rate of change.

-------------

Now let's find the slope for the table.

Focus on the rows for x = 0 and x = 3. They lead to f(x) = 10 and f(x) = 4 respectively.

We have (0,10) and (3,4) as our two points this time.

(x_1,y_1) = (0,10) \text{ and } (x_2,y_2)  = (3,4)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{4 - 10}{3 - 0}\\\\m = \frac{-6}{3}\\\\m = -2\\\\

We get the same slope as before, so we have the same rate of change.

Notice the change in y (-6) is the same as before. So we could pick any two y values we want as long as there's a gap of 6 between them, and the second y value is smaller than the first.

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Artemon [7]

Answer:

Answer in explanation.

Step-by-step explanation:

Lets take

y =  \frac{3}{4} x - 5

as L1.

Take L2 the line perpendicular to L1.

Standard form of equation of line:

y=mx+c, where m = slope and c = y-intercept.

Since L1 and L2 are perpendicular,

mL1 x mL2 = -1

Substitute mL1 into the equation,

3/4 x mL2 = -1

mL2 = -1 ÷ 3/4

mL2 = -4/3

L2 : y = mx+ c

Substitute y = 6, x = 8 and m = -4/3 into the equation,

6 =  -  \frac{4}{3} (8) + c \\ 6 = -  \frac{32}{3}  + c \\ c = 6 +  \frac{32}{3}  \\  = 16 \frac{2}{3}

therefore L2:

y =  -  \frac{4}{3}x   + 16 \frac{2}{3}

Lets take L3 as the line parallel to L1.

Since L3 and L1 are parallel,

mL3 = mL1 = 3/4

equation of line: y = mx+c

substitute y = 6, x = 8 and m = 3/4 into equation.

6 = ( \frac{3}{4} )(8) + c \\ 6 = 6 + c \\ c = 6 - 6 \\  = 0

therefore L3:

y =  \frac{3}{4} x

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Step-by-step explanation:

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In a certain soccer tournament you play 6 games. In every match you get 3 points if you win, 1 point for a draw and 0 points if
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Answer:

0.430625 = 0.431

Step-by-step explanation:

Let W represent winning, D represent a draw and L represent a loss.

12+ points can be garnered in each of the following ways.

6W 0D 0L

5W 1D 0L

5W 0D 1L

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4W 1D 1L

4W 0D 2L

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The probability of getting 12+ points is the sum of all these 7 probabilities.

Knowing that P(W) = 0.5

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P(6W 0D 0L) = [6!/(6!0!0!)] 0.5⁶ 0.1⁰ 0.4⁰ = 0.015625

P(5W 1D 0L) = [6!/(5!1!0!)] 0.5⁵ 0.1¹ 0.4⁰ = 0.01875

P(5W 0D 1L) = [6!/(5!0!1!)] 0.5⁵ 0.1⁰ 0.4¹ = 0.075

P(4W 2D 0L) = [6!/(4!2!0!)] 0.5⁴ 0.1² 0.4⁰ = 0.09375

P(4W 1D 1L) = [6!/(4!1!1!)] 0.5⁴ 0.1¹ 0.4¹ = 0.075

P(4W 0D 2L) = [6!/(4!0!2!)] 0.5⁴ 0.1⁰ 0.4² = 0.15

P(3W 3D 0L) = [6!/(3!3!0!)] 0.5³ 0.1³ 0.4⁰ = 0.0025

The probability of getting 12+ points = 0.015625 + 0.01875 + 0.075 + 0.09375 + 0.075 + 0.15 + 0.0025 = 0.430625

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