First step, write down the expression on one line, using necessary parentheses.
(2^8*5^(-5)*19^0)^(-2) * (5^(-2)/2^3)^4 *2^28
The apply the PEMDAS rule to simplify according to priority:
1. Parentheses
2. Exponentiation
3. Multiplication and Division (left to right)
4. Addition and Subtraction (left to right)
For exponentiation, it is convenient to convert all negative exponents to positive by taking the reciprocal, for example,
a^(-2)= 1/(a^2)
So
(2^8*5^(-5)*19^0)^(-2) * (5^(-2)/2^3)^4 *2^28
=1/[(2^8*5^(-5)*19^0)^(2)] * (1/[5^2*2^3])^4 *2^28
=5^5/[(2^8*19^0)^(2)] * (1/[5^2*2^3])^4 *2^28
Remember positive numbers raised to power zero equals 1, e.g.
a^0=a for any number a.
so 19^0=1
=5^10/[(2^8)^(2)] * (1/[5^2*2^3])^4 *2^28
Now, powers raised to a power equals the product of the powers, e.g.
(2^8)^2=2^16, (5^2)^4=5^8, (2^3)^4=2^12...
continuing,
=5^10/[2^16] * 1/[5^8*2^12] *2^28
When we have exponents to the same base in the denominator and numerator, we subtract exponents, e.g.
5^5/5^8=5^(5-8)=5^(-3), 2^28/[2^16*2^12]=2^(28-16-12)=2^0=1
so we get rid of many terms this way
continuing
=5^(10-8)*2^(28-16-12)
=5^2*2^0
=25*1
=25
Answer:
Equilateral triangles, squares and regular hexagons are the only regular polygons that will tessellate. Therefore, there are only three regular tessellations.
Step-by-step explanation:
Answer:
Totally Rational
Step-by-step explanation:
-16/-2 would give you 8 which is a rational number
<em><u>I hope this helps, dont hesitate to ask for any question.Mark me as brainliest is appreciated.Tq!!</u></em>
Answer:
A x-198,y-99
Step-by-step explanation:
since sin p/h you can say
perpendicular is 99
and hypotenuse is x
sin 30=99/x
x=198
and cos is b/h
base is y
and hypotenuse is x
cos 30=y/198
y-99
