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inessss [21]
3 years ago
5

12 is 90% of what number? with steps

Mathematics
1 answer:
a_sh-v [17]3 years ago
6 0

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>
  • Here 12 is 90% of a number.
  • So we can say that 90% of That number is 12 .
  • In this way we can get the the number
<h3><u>Solution</u><u>:</u><u>-</u></h3>

Let,

the number=x

<h3>According to the question ,</h3>

{:}\longrightarrow\sf 90\% \:of \;x=12

  • We know 90%=90/100
  • so add it

{:}\longrightarrow\sf {\dfrac {90}{100}}\times x=12

{:}\longrightarrow\sf {\dfrac {90x}{100}}=12

  • Now use cross multiplication method

{:}\longrightarrow\sf 90x=12\times 100

{:}\longrightarrow\sf 90x=1200

  • Now interchange sides .

{:}\longrightarrow\sf x={\dfrac {1200}{90}}

{:}\longrightarrow\sf x={\dfrac {200}{15}}

  • Answer will come in decimals so we take approximate value.

{:}\longrightarrow\sf x=13.3

{:}\longrightarrow\sf x=approximately \:13

\thereforeThe number is 13.

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find the value of "a" and "b" for which the limit exists both as x approaches 1 and as x approaches 2:
lbvjy [14]

Answer:

a = 4

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Step-by-step explanation:

If the given function is continuous at x = 1

\lim_{x \to 1^{-}} f(x)=(x+1)

                     =2

\lim_{x \to 1^{+}} f(x)=ax+b

                     =a+b

\lim_{x \to 1} f(x)=ax+b

                   =a+b

And for the continuity of the function at x = 1,

\lim_{x \to 1^{-}} f(x)=\lim_{x \to 1^{+}} f(x)=\lim_{x \to 1} f(x)

Therefore, (a + b) = 2 -------(1)

If the function 'f' is continuous at x = 2,

\lim_{x \to 2^{-}} f(x)=ax+b

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\lim_{x \to 2^{+}} f(x)=3x

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Subtract equation (1) from (2),

(2a + b) - (a + b) = 6 - 2

a = 4

From equation (1),

4 + b = 2

b = -2

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3 years ago
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