Given:
The figure of rectangle.
To find:
a. The diagonal of the rectangle.
b. The area of the rectangle.
c. perimeter of the rectangle.
Solution:
(a)
In a right angle triangle,
So, the diagonal of the of the rectangle is 24 units.
(b)
In a right angle triangle,
Length of the rectangle is 12 and width of the rectangle is 
. So, the area of the rectangle is:
So, the area of the rectangle is 
sq. units.
(c)
Perimeter of the rectangle is:
Therefore, the perimeter of the rectangle is about 65.57 units.
So what we gotta do is isolate the variable by
writing it out like this
4 1/4 25 those are the numbers where those go are like this
4x - 1/4 < 25 then move on to the next line on here we write out
4x + 1/4 - 1/4 < 25 + 1/4 (The reason why i put + 1/4 is because you have to isolate the variable by doing addition as well And i always find it easier to convert the fractions to decimals then after you make that line you make the next one like this you have to add 1/4 to 4x then take it away (which is 4x) then put that to the side like this 4x ? ? then we need to find those two ?s by adding 25 and 1/4 (or o.25) which is 25.25 then we need to add that to the second answer 4x ? 25.25 when you have this you need to find out which one is bigger so it is 4x<25.25 (or 25 1/4) then we need to divide 4 and 25.25 to get 6.25 so
the answer is x < 6.25 so c is your awnser
Answer:
Is not appropiate to refer a estimation or a statistic as a paramter because the statistic just give informaation about the sample selected and not about all the population of interest. What we can do is inference with this sample proportion or confidence intervals in order to see on what limits our real parameter of interest p lies.
Step-by-step explanation:
Description in words of the parameter p
represent the real population proportion of students who went Home for winter break
represent the estimated proportion of students who went Home for winter break
n is the sample size selected
The population proportion have the following distribution
Solution to the problem
For this case we assume that the proportion given 0.35 is an estimation for the real parameter of interest p, that means 
On this case the estimated proportion is calculated from the following formula:
Where X are the people in the sam with the characteristic desired (students who went Home for winter break) and n the sample size selected.
Is not appropiate to refer a estimation or a statistic as a paramter because the statistic just give informaation about the sample selected and not about all the population of interest. What we can do is inference with this sample proportion or confidence intervals in order to see on what limits our real parameter of interest p lies.
Answer:
The first bottle holds 25 3/5 ounces of water.
Step-by-step explanation:
16 x 8/5
= 16/1 x 8/5
= 128/5
= 25 3/5
