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ser-zykov [4K]
3 years ago
12

I really don't get what I'm supposed to do...​

Mathematics
2 answers:
Naddika [18.5K]3 years ago
8 0
Here’s the answer! :))
rusak2 [61]3 years ago
5 0

Answer:

check below

Step-by-step explanation:

1.  c = 68-27 = 41

2. t = 7.9+1.5 =9.4

3. a = 21*3 = 63

4. (multiply whole equation by 8) 8r+6=7, r=1/8

5. x = 25.2/4.2 = 6

6. b = 75/15 = 5

7. A. 6C = 99

B. C = 99/6 = $16.50

The solution represents the cost of one ticket.

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Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability that
Likurg_2 [28]
White       3/8
Green      2/8
Red          2/8
Blue          1/8

Blue         1/7
7 0
3 years ago
Determine the vertex- f( x)= x^2 +4x +3<br><br> (2,-1)<br> (-2, -1)<br> (-3, -1)<br> (-1, -2)
Grace [21]

The answer is ( -2 , -1 ) .

Hope it's helped ♥️♥️♥️♥️♥️.

8 0
3 years ago
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate a 5 8 per hour, so that the number o
timurjin [86]

Answer:

(a) P (X = 6) = 0.12214, P (X ≥ 6) = 0.8088, P (X ≥ 10) = 0.2834.

(b) The expected value of the number of small aircraft that arrive during a 90-min period is 12 and standard deviation is 3.464.

(c) P (X ≥ 20) = 0.5298 and P (X ≤ 10) = 0.0108.

Step-by-step explanation:

Let the random variable <em>X</em> = number of aircraft arrive at a certain airport during 1-hour period.

The arrival rate is, <em>λ</em>t = 8 per hour.

(a)

For <em>t</em> = 1 the average number of aircraft arrival is:

\lambda t=8\times 1=8

The probability distribution of a Poisson distribution is:

P(X=x)=\frac{e^{-8}(8)^{x}}{x!}

Compute the value of P (X = 6) as follows:

P(X=6)=\frac{e^{-8}(8)^{6}}{6!}\\=\frac{0.00034\times262144}{720}\\ =0.12214

Thus, the probability that exactly 6 small aircraft arrive during a 1-hour period is 0.12214.

Compute the value of P (X ≥ 6) as follows:

P(X\geq 6)=1-P(X

Thus, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8088.

Compute the value of P (X ≥ 10) as follows:

P(X\geq 10)=1-P(X

Thus, the probability that at least 10 small aircraft arrive during a 1-hour period is 0.2834.

(b)

For <em>t</em> = 90 minutes = 1.5 hour, the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 1.5=12

The expected value of the number of small aircraft that arrive during a 90-min period is 12.

The standard deviation is:

SD=\sqrt{\lambda t}=\sqrt{12}=3.464

The standard deviation of the number of small aircraft that arrive during a 90-min period is 3.464.

(c)

For <em>t</em> = 2.5 the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 2.5=20

Compute the value of P (X ≥ 20) as follows:

P(X\geq 20)=1-P(X

Thus, the probability that at least 20 small aircraft arrive during a 2.5-hour period is 0.5298.

Compute the value of P (X ≤ 10) as follows:

P(X\leq 10)=\sum\limits^{10}_{x=0}(\frac{e^{-20}(20)^{x}}{x!})\\=0.01081\\\approx0.0108

Thus, the probability that at most 10 small aircraft arrive during a 2.5-hour period is 0.0108.

8 0
3 years ago
Simplify picture down Below ​
krok68 [10]

Answer:

x^{2}  

I hope this helps!

7 0
3 years ago
A poll that does not attempt to generate a random sample, but instead invites people to volunteer to participate is called:_____
Helga [31]

Answer:

Self selection sampling.

Step-by-step explanation:

A poll that does not attempt to generate a random sample, but instead invites people to volunteer to participate is called - self selection sampling.

Self-selection sampling is a sampling method where researchers allow the people or individuals, to choose to take part in research on their own accord.

6 0
3 years ago
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