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ser-zykov [4K]
3 years ago
12

I really don't get what I'm supposed to do...​

Mathematics
2 answers:
Naddika [18.5K]3 years ago
8 0
Here’s the answer! :))
rusak2 [61]3 years ago
5 0

Answer:

check below

Step-by-step explanation:

1.  c = 68-27 = 41

2. t = 7.9+1.5 =9.4

3. a = 21*3 = 63

4. (multiply whole equation by 8) 8r+6=7, r=1/8

5. x = 25.2/4.2 = 6

6. b = 75/15 = 5

7. A. 6C = 99

B. C = 99/6 = $16.50

The solution represents the cost of one ticket.

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A community college employs 88 ​full-time faculty members. To gain the​ faculty's opinions about an upcoming building​ project,
Ierofanga [76]

The numbers that would be included in the sample are 4, 1, 1, 4, 7, 9, 2, 6, 4, 7, 4, 4, 1, 0, 3, 0, 5, 0, 7, 1, 1, 6, 5, 4, 9

<h3>How to determine the number that will be included in the sample?</h3>

The complete question is added as an attachment

The given parameters are:

Row = 3

Column = 6

From the attached figure, the entries in row 3 are:

4, 1, 1, 4, 7, 9, 2, 6, 4, 7, 4, 4, 1, 0, 3, 0, 5, 0, 7 1

From the attached figure, the entries in column 6 are:

1, 6, 9, 5, 4, 9

Hence, the numbers that would be included in the sample are 4, 1, 1, 4, 7, 9, 2, 6, 4, 7, 4, 4, 1, 0, 3, 0, 5, 0, 7, 1, 1, 6, 5, 4, 9

Read more about samples at:

brainly.com/question/14470673

#SPJ1

3 0
2 years ago
What percent of 60 is 150?
nignag [31]
To work out what percent of 60 is 150 just do the following:

150 / 60 = 2.5
2.5 x 100 = 250

Therefore 150 is 250% of 60. Hope I helped!
5 0
4 years ago
SOMEBODY HELP ME WITH THESE PLEASE! I really need the help like NOW PLS!
snow_lady [41]
93. g(n) = n - 4
f(n) = 2n^2 - 5n

then g(n) +f(n) = (n-4) + (2n^2 - 5n)
                                = n - 4 + 2n^2 - 5n
                                = 2n^2 -5n + n - 4
                                = 2n^2 - 4n -4


95. f(n) = -n+3
      g(n) = n^3 + 3n
Then f(n) . g(n) = (-n+3) . (n^3 + 3n)
                                 = -n^4 + 3n^3 - 3n^2 + 9n
 

97. f(x) = 3x+1
g(x) = 2x
For finding f(g(x)) we will plugin value of g(x) in place of x in f(x).
f(g(x)) = 3*(2x) + 1
                  = 6x + 1


99. f(n) = n - 3
g(n) = 2n^2 - 3n

g(-7) = 2*(-7)^2 - 3 * (-7) = 2* 49 + 21 = 98 + 21 = 119
f(g(-7)) = 119 - 3 = 116

4 0
4 years ago
explain how to solve for the missing side from the similar figures given and solve. (do not just give the answer)
Paha777 [63]

Answer:

x=14

Step-by-step explanation:

Since the triangles are similar, you first line up the sides. Then, because the 16 and the 24 line up together, you divide them to find out how much bigger the first triangle is, which is 3/2 or 1.5. After that, you can see that the 21 and the x are on the same side, so you would divide 21 by 1.5 or 3/2 to get x. 21÷1.5=14.

x=14

7 0
3 years ago
Read 2 more answers
Use Lagrange multipliers to find the maximum and minimum values of the function subject to the given constraint. (If an answer d
eduard

The Lagrangian is

L(x_1,\ldots,x_n,\lambda_1,\ldots,\lambda_n)=x_1+\cdots+x_n+\lambda_1({x_1}^2+\cdots+{x_n}^2)+\cdots+\lambda_n({x_1}^2+\cdots+{x_n}^2)

with partial derivatives (set equal to 0)

\dfrac{\partial L}{\partial x_i}=1+2x_i(\lambda_1+\cdots+\lambda_n)=0

\dfrac{\partial L}{\partial\lambda_i}={x_1}^2+\cdots+{x_n}^2-36=0

for each 1\le i\le n.

Let \Lambda be the sum of all the multipliers \lambda_i,

\Lambda=\displaystyle\sum_{k=1}^n\lambda_k=\lambda_1+\cdots+\lambda_n

We notice that

x_i\dfrac{\partial L}{\partial x_i}=x_i+2{x_i}^2\Lambda=0

so that

\displaystyle\sum_{i=1}^nx_i\dfrac{\partial L}{\partial x_i}=\sum_{i=1}^nx_i+2\Lambda\sum_{i=1}^n{x_i}^2=0

We know that \sum\limits_{i=1}^n{x_i}^2=36, so

\displaystyle\sum_{i=1}^nx_i+2\Lambda\sum_{i=1}^n{x_i}^2=0\implies\sum_{i=1}^nx_i=-72\Lambda

Solving the first n equations for x_i gives

1+2\Lambda x_i=0\implies x_i=-\dfrac1{2\Lambda}

and in particular

\displaystyle\sum_{i=1}^nx_i=-\dfrac n{2\Lambda}

It follows that

-\dfrac n{2\Lambda}+72\Lambda=0\implies\Lambda^2=\dfrac n{144}\implies\Lambda=\pm\dfrac{\sqrt n}{12}

which gives us

x_i=-\dfrac1{2\left(\pm\frac{\sqrt n}{12}\right)}=\pm\dfrac6{\sqrt n}

That is, we've found two critical points,

\pm\left(\dfrac6{\sqrt n},\ldots,\dfrac6{\sqrt n}\right)

At the critical point with positive signs, f(x_1,\ldots,x_n) attains a maximum value of

\displaystyle\sum_{i=1}^nx_i=\dfrac{6n}{\sqrt n}=6\sqrt n

and at the other, a minimum value of

\displaystyle\sum_{i=1}^nx_i=-\dfrac{6n}{\sqrt n}=-6\sqrt n

4 0
4 years ago
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