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m_a_m_a [10]
3 years ago
13

Solve the following equation for the variable indicated 15 = Зn + 6р, for n

Mathematics
1 answer:
Taya2010 [7]3 years ago
8 0

Answer:

Solving the equation 15 = 3n + 6p for variable n we get \mathbf{n=5-2p}

Step-by-step explanation:

We need to solve the equation 15 = 3n + 6p for variable n

Solving:

15 = 3n + 6p

Subtract both sides by 6p

15-6p = 3n +6p -6p\\15-6p=3n

Switch sides of equality

3n=15-6p

Divide both sides by 3

\frac{3n}{3} =\frac{15-6p}{3}\\n=\frac{3(5-2p)}{3}\\n=5-2p

So, solving the equation 15 = 3n + 6p for variable n we get \mathbf{n=5-2p}

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Answer:

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Step-by-step explanation:

3 0
3 years ago
In the formula A(t) = A0ekt, A(t) is the amount of radioactive material remaining from an initial amount A0 at a given time t an
Alenkasestr [34]

Answer:  693 years

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

A(t) =A_0e^{kt}

k = rate constant

t = time taken for decomposition = 1

A_0 = Initial amount of the reactant

A_t = amount of the reactant left =A_0-\frac{0.1}{100}\times A_0=0.999A_0

0.999A_0=A_0e^{k\times 1}

0.999=e^k

k=-0.001year^{-1}

for half life : t=t_\frac{1}{2}

A_t=\frac{1}{2}A_o

Putting in the values , we get

\frac{1}{2}A_0=A_0e^{-0.001\times t_\frac{1}{2}

t_\frac{1}{2}=693 years

Thus half life of this isotope, to the nearest year is 693.

8 0
4 years ago
Please answer this correctly, and you'll recieve brainliest. I need the CORRECT answer.
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Answer:

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5 0
3 years ago
the number of girls in a class is 10 more than the number of boys. if there are 36 students in all, how many girls are there in
Akimi4 [234]

Answer:

23 Girls

Step-by-step explanation:

23 plus 13 equals 36 and 23 is 10 more than 13.

6 0
3 years ago
Read 2 more answers
A small airplane flies 1200 miles with an average speed of 300 miles per hour. 2 hours after the plane leaves, a Boeing 747 leav
inysia [295]

The small plane has the following parameters

Distance = 1200 miles

Speed = 300miles/hour

time = ?

\begin{gathered} \text{Speed =}\frac{dis\tan ce}{time} \\ time\text{= }\frac{1200}{300} \\ \text{time = 4 hours} \end{gathered}

If a Boeing 747 leaves 2 hours later, the total time becomes 4hours + 2 hours = 6 hours

Considering the distance of the small plane after 6 hours, we have

\begin{gathered} \text{distance = sp}eed\times\text{ time} \\ d\text{ = 300 }\times6 \\ d\text{ =1800 miles} \end{gathered}

So the total distance = 1800 miles

Hence the speed of the Boeing 747 will be

\begin{gathered} \text{Speed =}\frac{dis\tan ce}{time} \\ \text{distance = 1800 miles } \\ time\text{ = 2hours} \end{gathered}\begin{gathered} \text{speed = }\frac{1800}{2} \\ \text{speed = 900 miles/hour} \end{gathered}

The average speed of the Boeing 747 is 900 miles/ hour

8 0
1 year ago
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