Answer:
To calculate the vertex you can use the vertex form ( i searched about the vertex and found it) but i don't know how to use it so i used another method.
The vertex is where the function inverts (y values) so it is going to be or a maximum or a minimum of the function. To calculate the min/max you derivate the function and then equal it to zero.
1) y = -3x^2 -12x -10
the derivative of y is y' = -6x -12 = -6(x+2)
y'=0 <=> -6(x+2) = 0 <=> x+2=0 <=> x=-2
y(-2) = -3(-2)^2 -12*(-2) -10 = 2
So the vertex is the point (-2,2) .
Because the slope of the equation is negative that means that the vertex is going to be the maximum , so the maximum is (-2,2) .
To find another 4 points you just have to pick values of x and replace them in the equation y = -3x^2 -12x -10 to find y.
2) y = -2x^2 -12x -16
Do the same thing we did in point 1
y'= -4x-12 = -4(x+3)
y'=0 <=> -4(x+3) = 0 <=> x+3=0 <=> x=-3
y(-3) = -2(-3)^2 -12*(-3) -16 = 2
So the vertex is the point (-3,2) .
