The correct option is D.
When dissolving a substance in a solvent, stirring the solution will increased the rate at which the substance dissolved. This is because, when one stirs a solution, it exposes more surface area of the solute to the solvent, thus, increasing the interaction between the solute and the solvent. The higher the quantity of the solute that is exposed to the solvent, the higher the rate of dissolution of the solute.
Answer : The molarity of the ion is
Explanation : Given,
Density of sample = 1.00 g/mL
Concentration of = 42 mg/kg
First we have to calculate the volume of sample.
Let us assume that the mass of sample be 1 kg or 1000 g.
(1 L = 1000 mL)
Now we have to calculate the moles of
As we are given that,
Mass of in 1 kg of sample = 42 mg = 0.042 g
Molar mass of Ca = 40 g/mole
Now we have to calculate the molarity of the ion.
Therefore, the molarity of the ion is
Answer:
Phosphorus is in group VA so it has 5 valence electrons and Oxygen is in group VIA so each oxygen has 6 valence electrons. Total valence electrons = 5 + 4(6) = 29
Explanation:
Answer : The concentration of at equilibrium is, 0.00154 M
Explanation :
First we have to calculate the diluted concentration.
where,
are the initial molarity and volume of .
are the final molarity and volume of diluted .
We are given:
Putting values in above equation, we get:
Now we have to calculate the concentration of at equilibrium.
The given chemical reaction is:
Initial conc. 0.0454 0
At eqm. (0.0454-x) x
The expression for equilibrium constant is:
Now put all the given values in this expression, we get:
x = 0.00154 M
Thus, the concentration of at equilibrium is, 0.00154 M
Answer:
<u>T2 = 745 K</u>
Explanation:
This is an ideal gas law problem. We can use this formula to find our answer:
(P1*V1)/T1 = (P2*V2)/T2
So we have these given in the problem:
P1 = 78 atm P2 = 45.2 atm
V1 = 21 L V2 = 30.0 L
T1 = 900 K T2 = ?
So we put all of this stuff into the equation and solve for the unknown T2:
[(78 atm)*(21 L)]/(900 K) = [(45.2 atm)*(30.0 L)]/T2
(1638 atm*L)/900 K = (1356 atm*L)/T2
1.82 atm*L/K = (1356 atm*L)/T2
[flip around to put T2 on the numerator and alone]
T2 = (1356 atm*L)/1.82 atm*L/K
[atm*L cancel out to leave us with K]
T2 = 745.0549451
<u>T2 = 745 K</u>