Answer: Combine like terms
Take both h values (1h) + (-2h) and (5) + (3)
-h + 8
The number of possible groups or combination of three men can be formed from 10 is 120.
According to the given question.
Total number of men in a company, n = 10.
Number of men to be selected, r = 3
As we know that, What is a combination in math?
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A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter.
Therefore, the number of possible groups or combination of three men can be formed from 10
=
= 10!/ 3!7!
= 10(9)(8)/3(2)
= 5 × 3 × 8
= 120
The number of possible groups or combination of three men can be formed from 10 is 120.
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Given inequality is
Now we need to find the graph of .
Which can be done into two parts:
First graph the line then shade the graph for inequality sign
Graph the line
we can plug any number for x say x=0 to find the y-value
4x-8y=9
4*0-8y=9
0-8y=9
-8y=9
y=-1.125
Hence first point is (0,-1.125)
Similarly we can plug y=0 then solve for x
4x-8y=9
4x-8*0=9
4x-0=9
4x=9
x=2.25
hence 2nd point is at (2.25,0)
Now graph both points and join them by a straight line.
Since used inequality is so we use solid line not the dotted line.
Shading the graph:
we can pick any test point which is not on the line 4x-8y=9 say (0,0) then plug into original problem to see if that point satisfies the original problem or not.
Which is TRUE.
TRUE means shade in direction of test point otherwise we graph in opposite direction of test point.
Now final graph will look like the graph attached below: