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Nata [24]
3 years ago
5

Which of the following is a linear function

Mathematics
2 answers:
Feliz [49]3 years ago
3 0

Answer:

f(x)=5x-6

Step-by-step explanation:

When I entered this in Desmos it crossed through the line crossed  through the x and y axis which makes this equation a linear function.

sergey [27]3 years ago
3 0

Answer:

f(x) = 5x - 6

Step-by-step explanation:

The first function is a Linear Function

The second function is a Exponential Function

The third is an Inverse Function

The forth is a Quadratic Function

Hope this helps!

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Using place value to exchange equal amounts when renaming a number is called
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<span>Using place value to exchange equal amounts when renaming a number is called : Regroup Simple example for a group is when you try to add up : 86 + 25 86 has 8 group of tens and 6 groups of one 25 has 2 groups of tens and 5 groups of one after adding that up , now the number has 11 group of tens and 1 group of one, the result of that equation would be : 110</span>
3 0
3 years ago
What is the value of j in the equation j + j + 14 = 3 j + 10?
Aleksandr-060686 [28]
2j+14=3j+10
14-10=3j-2j
4=j D

good luck..
4 0
3 years ago
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Solve the equation 4x +30 = 2(x-10)
snow_tiger [21]
4x+30=2(x-10)
4x+30=2x-20
4x-2x= -30-20
2x= -50
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Mark as brainliest if you find it helpful.

4 0
3 years ago
Help please asap with this​
Allushta [10]
Use photo math app it will help you

The second one 1.7 = 17/10
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5 0
3 years ago
Can someone help me
erik [133]

Answer:

   6 < x < 23.206

Step-by-step explanation:

To properly answer this question, we need to make the assumption that angle DAC is non-negative and that angle BCA is acute.

The maximum value of the angle DAC can be shown to occur when points B, C, and D are on a circle centered at A*. When that is the case, the sine of half of angle DAC is equal to 16/22 times the sine of half of angle BAC. That is, ...

  (2x -12)/2 = arcsin(16/22×sin(24°))

  x ≈ 23.206°

Of course, the minimum value of angle DAC is 0°, so the minimum value of x is ...

  2x -12 = 0

  x -6 = 0 . . . . . divide by 2

  x = 6 . . . . . . . add 6

Then the range of values of x will be ...

  6 < x < 23.206

_____

* One way to do this is to make use of the law of cosines:

  22² = AB² + AC² -2·AB·AC·cos(48°)

  16² = AD² + AC² -2·AD·AC·cos(2x-12)

The trick is to maximize x while satisfying the constraints that all of the lengths are positive. This will happen when AB=AC=AD, in which case the equations be come ...

  22² = 2·AB²·(1-cos(48°))

  16² = 2·AB²·(1 -cos(2x-12))

The value of AB drops out of the ratio of these equations, and the result for x is as above.

4 0
3 years ago
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