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3 years ago

Value of 2^3can any one tell

Mathematics

2 answers:

Dahasolnce [82]3 years ago

8 0

Answer:

Step-by-step explanation:

2^3 = 2*2*2 = 8

Flauer [41]3 years ago

7 0

$\huge\boxed{\boxed{Hello\;there!}}$

We are asked to calculate

2^3 (2 cubed)

2 cubed is 2 times 2 times 2.

2 times 2 is 4, and 4 times 2 is 8.

So, 2³=8

Remember, 2³ is $\huge\bold{NOT}$ the same as 2*3.

$\huge\bold{Hope\;it\;helps\;you!}$

$\bold{Good\;luck! :)}$

$\huge\rm{StillEnjoyingLife :)$

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4 years ago

Read 2 more answers

Determine whether the following probability experiment represents a binomial experiment and explain the reason for your answer.S

kozerog [31]

Answer:

B., C. and D.

Step-by-step explanation:

Seven cards are selected from a standard 52-card deck without replacement. The number of diamonds selected is recorded. Does the probability experiment represent a binomial experiment?

The criteria for a Binomial experiment are the following.

1. Fixed number of trials. (Not met)

The text doesn't specify the sample size (it says that seven cards are selected but doesn't specify how many times will seven cards be drawn), this number must be established before starting the experiment.

2. There are only two possible outcomes for each trial. (Not met)

"Draws seven cards and records the number of diamonds" so the outcome of the trial can be

"No diamonds"

"1 diamond card"

"2 diamond cards"

"3 diamond cards"

...

"7 diamond cards"

Simply speaking, it has two outcomes if you can phrase it as a yes or no question. That is not the case in this experiment.

3. Each trial is an independent event. (Not met)

4. The probability of success in the same from one trial to another. (Not met)

Two events are independent if the occurrence of one doesn't affect the probability of occurrence of the next one.

Since the cards are selected without replacement, at each repetition of the trial the probability of the next trial is modified. Therefore, the trials are dependant and the probability of success is modified after each trial.

None of the criteria for a Binomial experiment are met, this is not a Binomial experiment.

I hope you have a SUPER day!

3 0

4 years ago

Find all the real values of X for which f(x)=0 F(x)= x^3-x

Natalka [10]

Answer:

x=0,1,-1

Step-by-step explanation:

It factors as

X(x+1)(x-1)=0

5 0

3 years ago

Translate the word phrase into a variable expression. seven less than the quotiont of x and 9

aev [14]

Quotient of x and 9= $\frac{x}{9}$

And 7 less than from it means= $\frac{x}{9} - 7$ (Answer)

8 0

3 years ago

Consider this scenario: The population of a city increased steadily over a ten-year span. The following ordered pairs show the p

vova2212 [387]

Answer:

Regression function: $y=1986.406+0.0059x$

The function predicts that population will reach 14,000 in year 2068.

Step-by-step explanation:

We have to determine a function $y=b_0+b_1x_1$ by applying linear regression. The data we have is 5 pair of points which relates population to year.

According to the simple regression model (one independent variable), if we minimize the error between the model (the linear function) and the points given, the parameters are:

$b_0=\bar{y}+b_1\bar{x}\\\\b_1=\frac{\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}}{\sum\limits^5_{i=1} {(x_i-\bar x)^2}}$

We start calculating the average of x and y

$\bar x=\frac{2500+2650+3000+3500+4200}{5}=\frac{15850}{5}=3170\\\\ \bar y=\frac{2001+2002+2004+2007+2011}{5}=\frac{10025}{5}=2005$

The sample covariance can be calculated as

$\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=(2500-3170)(2001-2005)+(2650-3170)(2002-2005)+(3000-3170)(2004-2005)+(3500-3170)(2007-2005)+(4200-3170)(2011-2005)\\\\\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=2680+1560+170+660+6180\\\\ \sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=11250$

The variance of x can be calculated as

$\sum\limits^5_{i=1} {(x_i-\bar x)^2}=(2500-3170)^2+(2650-3170)^2+(3000-3170)^2+(3500-3170)^2+(4200-3170)^2\\\\\sum\limits^5_{i=1} {(x_i-\bar x)^2}=448900+270400+28900+108900+1060900\\\\\sum\limits^5_{i=1} {(x_i-\bar x)^2}=1918000$

Now we can calculate the parameters of the regression model

$b_1=\frac{\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}}{\sum\limits^5_{i=1} {(x_i-\bar x)^2}}=\frac{11250}{1918000}=0.005865485 \\\\ b_0=\bar{y}+b_1\bar{x}=2005-0.005865485*3170=1986.406413$

The function then become:

$y=1986.406+0.0059x$

With this linear equation we can predict when the population will reach 14,000:

$y=1986.406+0.0059(14,000)=1986.406+82.117=2068.523$

6 0

3 years ago

Value of 2^3can any one tell​

Value of 2^3can any one tell