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Oliga [24]
3 years ago
10

Does anyone know how to solve this?

Mathematics
2 answers:
tekilochka [14]3 years ago
7 0

Answer:

car 1 = 173.08 liters

car 2 = 76.92 liters

Step-by-step explanation:

the first step is to find what ratio of car 1 is to car 2

that is 18:8

total ratio is 26

the combination of car 1 and 2 = 26

the total km = 3350

total fuel = 250 liters

car 1 = <u>18 x 250</u> liters

                26

= 173.08 liters

car 2 =<u> 8 x 250</u> liters

                26

= 76.92 liters

173.08 + 76.92 = 250

Wittaler [7]3 years ago
5 0

Answer:

first car : 115 liters

second car: 135 liters

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Answer:

a) \bar X = 121.4

b) SE = \frac{\sigma}{\sqrt{n}}= \frac{15}{\sqrt{40}}=2.372

c) 121.4-1.64\frac{15}{\sqrt{40}}=117.51    

121.4+1.64\frac{15}{\sqrt{40}}=125.29  

Step-by-step explanation:

Data given: 126,111,141,96,123,115,116,113,127,114,122,116,104,126,126,132,139,111,143,121,119,107,154,125,120,135,142,132,94,103,143,115,132,107,118,105,101,135,94,153

Part a

For this case we can calculate the sample mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And after replace we got:

\bar X = 121.4

Part b

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

For this case we assume that the population deviation is \sigma=15, we can calculate the standard error with this formula:

SE = \frac{\sigma}{\sqrt{n}}= \frac{15}{\sqrt{40}}=2.372

Part c

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Now we have everything in order to replace into formula (1):

121.4-1.64\frac{15}{\sqrt{40}}=117.51    

121.4+1.64\frac{15}{\sqrt{40}}=125.29  

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