Y=3x-2
y=3(4)-2
y=12-2
y=10
I hope this helps.
If you nee solving it will be:
c^6(-3c^5)^2
c^6(3c^5)^2
c^6·3^2(c^5)^2
c^6·9(c^5)^2
c^6·9c^10
9c^6c^10
9c^6+10
9c^16
So the answer is:
9c^16
(9c to the power of 16)
Sorry I was late..
Answer:
0, 1, 2
Step-by-step explanation:
Euclid's division Lemma states that for any two positive integers ‘a’ and ‘b’ there exist two unique whole numbers ‘q’ and ‘r’ such that , a = bq + r, where 0≤ r < b.
Here, a= Dividend, b= Divisor, q= quotient and r = Remainder.
According to Euclid's division lemma a 3q+r, where 0≤r≤3 and r is an integer.
Therefore, the values of r can be 0, 1 or 2.
Answer:
11. 2/5 = <u>40</u>/100 = <u>40</u>% 12. 29/50 = <u>58</u>/100 = <u>58</u>%
Step-by-step explanation:
To convert the given fraction to a fraction of 100, cross-multiply and divide.
2 × 100 = 200 / 5 = 40
Then, whenever you have a number over 100, all you need to do to get the percentage is find the numerator and add a percent sign at the end of the number.
40 ⇒ 40%
Repeat this with the second question.
29 × 100 = 2900 / 50 = 58 ⇒ 58%
