General equation of parabola: y-k = a(x-h)^2
Here the vertex is at (0,0), so we have y-0 = a(x-0)^2, or y = ax^2
All we have to do now is to find the value of the coefficient a.
(1,2) is on the curve. Therefore, 2 = a(1)^2, or 2 = a(1), or a = 2.
The equation of this parabola is y = 2x^2.
Elimination:
-4x+y=6
-5x-y=21 ...and then u add them together so its;
(the y cancelled out so its 0) x =27
plug in the 27 to any x...
-4(27) + y = 6
-108+y=6
add -108 on both sides so its...
y= -102
(27, -102)
Hope this helped :)
Answer:
Step-by-step explanation:
a₁ = -3 = (-1)¹×3
a₂ = 6 = (-1)²×2×3
a₃ = -28 = (-1)³×2²×7
a₄ = 72 = (-1)⁴×2³×3²
a₅ = -360 = (-1)⁵×2³×3²×5
a₆ = 2160 = (-1)⁶×2⁴×3³×5
That's as far as I got. I can predict that a₇ is a multiple of -32 and a₈ is a multiple of 64, but I don't see the pattern with the other factors.
(6-3)÷3-6+2
3÷3-6+2
1-6+2
-5+2
-3
