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vladimir2022 [97]
3 years ago
5

How do you solve addition equations using models?

Mathematics
1 answer:
Yuri [45]3 years ago
5 0

Answer:

Show blocks as addends and the sum as a bigger block

Step-by-step explanation:

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Help on 9 & 10 please!
Mandarinka [93]

Step-by-step explanation:

9. x and z are equal. y+z=90

   148-x=180 x+148 are supplementary

   -148    -148 Subtract 148 from both sides to isolate x

         x=32 degrees

         z=32 degrees b/c x and z are equal

 y+z=90 y and z are complementary

 y+(32)=90 Substitute 32 in for z

   -32     -32

 y         =58 degrees

10. (4x-25)=(2x+7) B/c of the bisection, the two angles are equal.

     4x-25  =2x+7 Remove parenthesis

      -2x       -2x Subtract 2x from both sides

     2x-25  =    +7

          +25       +25 Add 25 to both sides to isolate x

    2x         =     32

     /2                 /2 Divide both sides by 2 to isolate x

     x            =     16

 (4(16)-25)+(2(16)+7)=78 degrees Substitute 16 into the equation, this time adding the values instead of setting them equal to get the angle measure requested.

11. (6x-47)+(x+4)=90 Angles that are complementary add up to 90 degrees

    7x-43            =90 Add like terms

         +43             +43 Add 43 to both sides to isolate x

   7x                    =133

   /7                       /7 Divide both sides by 7 to isolate x

     x                     =19

((19)+4)=23 degrees Substitute x into the angle measure requested

12. 180=2x-9+x Use the words to help you determine what each value is.

     180=3x-9 Add like terms

     +9        +9 Add 9 to both sides to isolate x

     189=3x

     /3     /3 Divide both sides by 3 to isolate x

     63=x

 2(63)-9=177 degrees Substitute 63 into x to find the requested angle measure.

3 0
2 years ago
Use variation of parameters to find a general solution to the differential equation given that the functions y1 and y2 are linea
Aleks [24]

Recall that variation of parameters is used to solve second-order ODEs of the form

<em>y''(t)</em> + <em>p(t)</em> <em>y'(t)</em> + <em>q(t)</em> <em>y(t)</em> = <em>f(t)</em>

so the first thing you need to do is divide both sides of your equation by <em>t</em> :

<em>y''</em> + (2<em>t</em> - 1)/<em>t</em> <em>y'</em> - 2/<em>t</em> <em>y</em> = 7<em>t</em>

<em />

You're looking for a solution of the form

y=y_1u_1+y_2u_2

where

u_1(t)=\displaystyle-\int\frac{y_2(t)f(t)}{W(y_1,y_2)}\,\mathrm dt

u_2(t)=\displaystyle\int\frac{y_1(t)f(t)}{W(y_1,y_2)}\,\mathrm dt

and <em>W</em> denotes the Wronskian determinant.

Compute the Wronskian:

W(y_1,y_2) = W\left(2t-1,e^{-2t}\right) = \begin{vmatrix}2t-1&e^{-2t}\\2&-2e^{-2t}\end{vmatrix} = -4te^{-2t}

Then

u_1=\displaystyle-\int\frac{7te^{-2t}}{-4te^{-2t}}\,\mathrm dt=\frac74\int\mathrm dt = \frac74t

u_2=\displaystyle\int\frac{7t(2t-1)}{-4te^{-2t}}\,\mathrm dt=-\frac74\int(2t-1)e^{2t}\,\mathrm dt=-\frac74(t-1)e^{2t}

The general solution to the ODE is

y = C_1(2t-1) + C_2e^{-2t} + \dfrac74t(2t-1) - \dfrac74(t-1)e^{2t}e^{-2t}

which simplifies somewhat to

\boxed{y = C_1(2t-1) + C_2e^{-2t} + \dfrac74(2t^2-2t+1)}

4 0
3 years ago
1. Find the angle for insurance and taxes
Naddika [18.5K]

Answer:

3+3+5+16+28+22=77

100-77=23% for insurance and taxes

23/100 x 360= 82.8 degrees

If clothing is 3%, do that % over 100 x $40,000 to get how much spent.

3/100 x 40000= $1200 on clothes

6 0
2 years ago
Line t has a slope of -9/2 line u is parallel to t what is the slope of u
erik [133]

Answer:

the slope of the parallel line would also be -9/2

Step-by-step explanation:

5 0
3 years ago
Please help I’ll mark you as brainliest if correct!
schepotkina [342]
Increases by +2
Its arithmetic
Sixth number would be 17+2=19
Seventh is 19+2=21
Eighth is 21+2=23

6 0
2 years ago
Read 2 more answers
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