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denis23 [38]
3 years ago
8

Match each binomial expression with the set of coefficients of the terms obtained by expanding the expression.

Mathematics
2 answers:
user100 [1]3 years ago
8 0

 explanation:

(A) (2x+y)^3=8 x^3 + 12 x^2 y + 6 x y^2 + y^3

Answer option C)  8, 12, 6, 1

B) (2x+3y)^4 = 16 x^4 + 96 x^3 y + 216 x^2 y^2 + 216 x y^3 + 81 y^4

Answer option D) 16, 96, 216, 216, 81

C) (3x+2y)^3 = 27 x^3 + 54 x^2 y + 36 x y^2 + 8 y^3

Answer option B) 27, 54, 36, 8

D)(x+y)^4 = x^4 + 4 x^3 y + 6 x^2 y^2 + 4 x y^3 + y^4

Answer option A) 1, 4, 6, 4, 1

andreev551 [17]3 years ago
3 0
(A) (2x+y)^3 = (C) 8, 12, 6, 1
(B) (2x+3y)^4 = (D) 16, 19, 216, 216, 81
(C) (3x+2y)^3 = (B) 27, 54, 36, 8
(D) (x+y)^4 = (A) 1, 4, 6, 41
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I need help with number 1-4 I don’t understand..
Karo-lina-s [1.5K]

Answer:

  1. 109°, obtuse
  2. 131°, obtuse
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Step-by-step explanation:

You are exected to know the relationships of angles created where a transversal crosses parallel lines.

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The appearance of the diagram often gives you a clue.

You also expected to know the name (or category) of angles less than, equal to, or greater than 90°. Respectively, these are <em>acute</em>, <em>right</em>, and <em>obtuse</em> angles.

1. Adjacent angles are supplementary. The supplement of the given angle is 109°, so x will be obtuse.

2. Opposite exterior angles are equal, so y will be 131°. It is obtuse.

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4. Corresponding angles are equal, so x will be 124°. It is obtuse.

8 0
3 years ago
Running out of time! Please help and show work! Thank you! Will mark brainliest!
VikaD [51]
<h3>​(-3j²k³)²(2j²k)³</h3>

(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.​</em>

​= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>

​= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>

= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.​</em>

= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹​

​Answer = 72j¹⁰k⁹

​Hope this helps!​​​​

​​\textit{\textbf{Spymore}}​​​​​​

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