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weqwewe [10]
3 years ago
11

Pls!!!!! Answer this I only have like 10 minutes. Pls no links either. I really need help pls!!!

Mathematics
1 answer:
Serjik [45]3 years ago
4 0

Answer:

y-intercept = 2

slope = 3/4

y = 3/4x + 2

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Jenny has c charms on her bracelet. Her older sister has 5 more charms than Jenny. Write an expression that shows how many charm
Svetradugi [14.3K]
Answer-

C + 5 = x

C showing how many charms Jenny has on her bracelet.
5 for the number of how many more her sister has.
X for the final sum.
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1 year ago
To burn 1 molecule of c7h16 to form co2 and h2o (complete combustion), how many molecules of o2 are required?
Irina18 [472]

The complete balanced chemical reaction is:

<span>C7H16  +  3O2  -->  7CO2  +  8H2O</span>

 

So 3 moles of oxygen O2 is required for every 1 mole of C7H16. In the same manner, 3 molecules of O2 is required for every 1 molecule of C7H16.

 

Answer:

<span>3 molecules O2 </span>

5 0
2 years ago
Hep please I need it fast too
kozerog [31]
The value of the expression decreases
4 0
3 years ago
Find the volume of the composite figure. Explain your thought, explain how your arrived at your answer. SHOW YOUR WORK FOR FULL
Bond [772]

At the bottom of the composite figure we have half a sphere, of radius 10 in.

The volume of this hemisphere would be half the volume of the full sphere, or:

(1/2)(4/3)π(10 in)^3, or (2/3)π(1000 in^3), or (2000/3)π in^3.

On top is the cone of radius 10 and slant height 15 in. To find the volume of this cone-shaped solid, we'll need the height of the cone. This can be found using the Pyth. Thm. as follows:

15^2 = 10^2 + h^2, where h is the height of the cone.

225 = 100 + h^2, so that h= √125, or 5√5. The height of the cone is 5√5 in.

Then the volume of the cone is V = (1/3)(base)(height)

= (1/3)(π)(100 in^2)(5√5 in)

= 500√5/3(π) in^3


The total volume of the composite solid is then

(2000/3)(π in^3) + ( 500√5/3(π) ) in^3), or

(π/3)(4+√5) in^3. This comes out to 6.53 in^3, to the nearest hundredth.

7 0
2 years ago
If n(A-B)=18,n(AuB)=70 and n(AnB)=25 then find n(B)
svp [43]

n(A-B) denotes elements which are in A but not in B

n(Au B) denotes elements in A and B

n(AnB) denotes elements that are common in A and B

Now I will add one more set

n(B-A) which denotes elements in B but not in A

So, n(AuB) = n(A-B) + n( B-A) +n(AnB)

70 = 18 +n(B-A) + 25

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n(B-A) = 70-43

n(B-A) = 27

So, n(B) = n( B-A) + n( AnB)

= 27+25

= 52

4 0
3 years ago
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