What are the building blocks of ionic crystals

1. Explain how you would make 550 ml of a 0.15 M NaOH solution. an

Leona [35]

Add 3.3g of NaOH to 550 mL of water.

6 0

4 years ago

Even at high T, the formation of NO is not favored:

Readme [11.4K]

Answer:

3,16x10⁻³M

Explanation:

For the reaction:

N₂(g) + O₂(g) ⇄ 2NO(g). The kc is defined as:

kc = [NO]² / [N₂] [O₂] = 4,10x10⁻⁴ (1)

If you add in a 1,0L container 0,25 mol of N₂ and 0,10 mol of O₂, concentrations in equilibrium will be:

[N₂] = 0,25M - x

[O₂] = 0,10M - x

[NO] = 2x

Replacing in (1):

[2X]² / [0,25-x] [0,10-x] = 4,10x10⁻⁴

[2X]² / 0,025 - 0,35x + x²= 4,10x10⁻⁴

4X² = 4,10x10⁻⁴x² - 1,435x10⁻⁴x + 1,025x10⁻⁵

3,99959x² + 1,435x10⁻⁴x - 1,025x10⁻⁵ = 0

Solving for x:

x = -0,0016 (Wrong answer, there is no negative concentrations)

x = 0,00158 (Right answer)

As molar concentration of NO in equilibrium is 2x:

[NO] = 2x = 2×0,00158 = 3,16x10⁻³M

I hope it helps!

6 0

4 years ago

Oxidation number of the sulfur and chloride in the sulfur tetrachloride?

yuradex [85]

Answer:

SCl4

oxidation state of sulphur=+4

oxidation state of chlorine=-4

oxidation state of one chlorine atom=-1

6 0

3 years ago

What is the mole fraction of each component in a solution made by mixing 300 g of ethanol(C2H5OH) and 500 g of water?

Snowcat [4.5K]

Answer:

The mole fraction of ethanol and water in the solution are 0.19 and 0.81 respectively.

Explanation:

The Molar Fraction is a way of measuring the concentration that expresses the proportion in which a substance is found with respect to the total moles of the solution, which are calculated by adding the moles of solute (s) and solvent.

It is calculated by dividing the number of moles of one of the components by the total number of moles of the solution.

The sum of all the molar fractions of the substances present in a solution is equal to 1.

So, the expression to calculate the mole fraction is:

$Molar fraction (Xi)=\frac{moles of sudstance}{total moles of the solution}$

Being the molar mass of the compounds:

Ethanol 46 $\frac{g}{mol}$

Water 18 $\frac{g}{mol}$

the number of moles that represent the mass quantities is calculated as:

Moles of ethanol: 300 grams* $\frac{1 mol}{46 grams}$ = 6.52 moles
Moles of water: 500 grams* $\frac{1 mol}{18 grams}$ = 27.78 moles

So the total moles in solution are 6.52 moles + 27.78 moles = 34.3 moles

The mole fraction of ethanol in the solution is calculated as:

$mole fraction of ethanol=x_{ethanol} =\frac{6.52 moles}{34.3 moles}$

$x_{ethanol} =0.19$

The mole fraction of water in the solution is calculated as:

$mole fraction of water=x_{water} =\frac{27.78 moles}{34.3 moles}$

$x_{water} =0.81$

Then:

$x_{water} +x_{ethanol} = 0.81 + 0.19$

$x_{water} +x_{ethanol} =1$

The mole fraction of ethanol and water in the solution are 0.19 and 0.81 respectively.

.

8 0

3 years ago

Many food chains together create a______

Amanda [17]

Many food chains together create a food web.

hope this helps,, have a nice day :))

3 0

3 years ago