A salesperson is paid a base salary of $300 a week plus a 5% commission on the sales he generates. Which inequality best represe
nts s, the amount of sales in dollars he must generate to earn at least $500 for the week?
2 answers:
The expression can be written as the inequality:
300+0.05s≥500
300$ is made per week, so we start off with
300
He also makes 5% or 0.05 from his sales, so we add in the expression 0.05x (where s is equal to his sales volume for the week)
300+0.05s
If he wants to make at least 500$ weekly, then the total of the base salary plus the commission has to be 'greater than or equal to 500.
300+0.05s≥500
Lets solve for s now...
300+0.05s≥500
subtract 300 from both sides
0.05s≥200
Divide both sides by 0.05
s≥4000
$300 per week. 0.05%=5%
First, we have 300+0.05s≥500
300+0.05s≥500
300 0.05s-300 ≥500-300
0.05s<span>≥200</span>
Divide each side by 0.05
s≥4000
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I think the answer is 12
because
y=36, x=9
y=?, x=3
so you divide 36 by 3 to get the other y
Hope this helps
Answer:
x= 3 and x= -3
Step-by-step explanation:
x^2 -9 = 0
Factor x^2-9
(x+3)(x-3)
If x+3=0, then x= -3
If x-3=0, then x= 3
His new hourly rate will be $9.60
an = a1 +d(n-1)
a4 =a1+d(4-1)
-4 = -1+d(3)
add 1 to each side
-3 = 3d
d= -1
an = a1 +d(n-1)
an = -1 +-1 (n-1)
an = -1 -n +1
an = -n
Choice D
Three and twenty-nine ten-thousandths