Если вы хотите суму, сума 13 см, 16 см, 21 см, будет 50 см. Надо просто прибавить 16+13+21. Надеюсь что информатцыя подошла!!! Так круто што вы тоже говорите по русски!!! если возможно, нодпишите этот ответ как лутчый!!! спасибо!!
we can only make a rectangle because it is fully determined with the two side lengths, and we can make more than one unique parallelogram because we can make a rhombus with the given side lengths.
<h3>
Why is there only one rectangle with the given dimensions?</h3>
Remember that a rectangle is a parallelogram such that all the internal angles are 90°.
Now, a rectangle is only defined by two things which are the two side lengths, so, if the two side lengths are given like in this case (the side lengths measure 3 and 5). Then all the information about the rectangle is already given, which means that we have fully identified the one rectangle, that is why we can make only one rectangle with two given side lengths.
But, there are more shapes that can be made with these side lengths, we could have a rhombus with side lengths of 3 and 5, where the difference between the rhombus and the rectangle is that the internal angles of the rhombus are not necessarly equal to 90°.
Concluding, we can only make a rectangle because it is fully determined with the two side lengths, and we can make more than one unique parallelogram because we can make a rhombus with the given side lengths.
If you want to learn more about rectangles:
brainly.com/question/17297081
#SPJ1
Answer:
The given statement is true.
Step-by-step explanation:
A basic variable in a linear system is a variable that corresponds to a pivot column in the coefficient matrix.
The statement is true.
This statement is the definition of a basic variable.
We can also say that a basic variables are 'n' variables that can take any value other than zero.
Answer:
a1 = 39, a2 = 41, a3 = 43
The pair with the greatest sum is a2 + a3 = 41 + 43 = 84
Step-by-step explanation:
Let the first integer be a1 = a.
Let the second odd integer be a2 = a + 2
Let the third odd integer be a3 = (a + 2) + 2 = a + 4
The sum of three consecutive odd integers is 123.
123 = a1 + a2 + a3
123 = a + (a + 2) + (a + 4)
123 = 3a + 6
117 = 3a
a = 39
a1 = a = 39
a2 = a + 2 = 39 + 2 = 41
a3 = a + 4 = 39 + 4 = 43
The pair with the greatest sum is a2 + a3 = 41 + 43 = 84
Answer:
None
Step-by-step explanation:
it would simplify to 3=2x-3, which has no solutions.