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deff fn [24]
2 years ago
13

(Kinda need help ASAP)

Mathematics
1 answer:
denis23 [38]2 years ago
4 0

Answer:

Plzzzz answer fast......

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Please help! I will mark as brainliest IF answer is right. <3
kap26 [50]

you look too cute in the dp i like your face its very cute

4 0
2 years ago
Read 2 more answers
Tamara is at the store buying pencils. There is a package with 4 pencils that costs $6 or a package with 5 pencils that costs $7
Mkey [24]

In order to determine the cost of each pencil we have to divide the total cost for the package of pencils by the number of pencils contained

For the 4 pencils box:

Cost per pencil = Total cost/number of pencils

Cost per pencil = 6/4 = 1.5

Similarly, for the 5 pencils package:

Cost per pencil = 7/5 = 1.4

As you can see, the $7 package is better to buy, because each pencil costs $1.4, then, option A is the correct answer

8 0
1 year ago
A quantity a varies inversely as a quantity b, if, when b changes a changes in the inverse ratio. What happens to the quantity a
Julli [10]

Answer:

quantity a is halfed

Corrected question;

A quantity a varies inversely as a quantity b, if, when b changes a changes in the inverse ratio. What happens to the quantity a if the quantity b doubles?

Step-by-step explanation:

Analysing the question;

A quantity a varies inversely as a quantity b,

a ∝ 1/b

a = k/b ......1

when b changes a changes in the inverse ratio;

Since the change at the same ratio but inversely, k = 1

So, equation 1 becomes;

a = 1/b

If the quantity b doubles,

ab = 1

a1b1 = a2b2

When b doubles, b2 = 2b1

a1b1 = a2(2b1)

Making a2 the subject of formula;

a2 = a1b1/(2b1)

a2 = a1/2

Therefore, when b doubles, a will be divided by 2, that means a is halfed.

3 0
3 years ago
A) Use the definition of Laplace transform to find L{f }. (Do the integrals.) For what values of s is L{f } defined?f(t) = (2t+1
kiruha [24]

For the given function f(t) = (2t + 1) using definition of Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].

As given in the question,

Given function is equal to :

f(t) = 2t + 1

Simplify the given function using definition of Laplace transform we have,

L(f(t))s = \int\limits^\infty_0 {f(t)e^{-st} } \, dt

          =  \int\limits^\infty_0[2t +1] e^{-st} dt

          = 2\int\limits^\infty_0 te^{-st} + \int\limits^\infty_0e^{-st} dt

         = 2 L(t) + L(1)

L(1) = \int\limits^\infty_0e^{-st} dt

     = (-1/s) ( 0 -1 )

     = 1/s , ( s >  0)

2L ( t ) = 2\int\limits^\infty_0 te^{-st}

        =  2[t\int\limits^\infty_0 e^{-st} - \int\limits^\infty_0 ({(d/dt)(t) \int\limits^\infty_0e^{-st} \, dt )dt]

        =  2/ s²

Now ,

L(f(t))s = 2 L(t) + L(1)

          = 2/ s² + 1/s

Therefore, the solution of the given function using Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].

Learn more about Laplace transform here

brainly.com/question/14487937

#SPJ4

8 0
10 months ago
Gradinize cheese costs $1.28 per pound. How much would you pay for 7 pounds ?
Alenkasestr [34]

Answer:

I'm pretty sure the answer is 8.96

Step-by-step explanation:

1.28×7=8.96

8 0
3 years ago
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