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Ahat [919]
3 years ago
5

The total cost of an order of shirts from a company consists of

Mathematics
1 answer:
Luba_88 [7]3 years ago
4 0

Answer:

The cost of each shirt is the same regardless of how many shirts are ordered. The company provides the following examples to customers to help them ... Using only this information, determine the cost of ordering 200 shirts. Also ... a shirt company charges a one-time setup fee plus a certain price per shirt.

Step-by-step explanation:

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Which of these is equal to ⅔ × ¾ × ⅗?
Sphinxa [80]

Answer:

3/10

Step-by-step explanation:

Just multiply all of the numerators (top numbers)  and then multiple all of the denominators (bottom numbers)

2/3x3/4x3/5  would be 18/60 Then take any number that is a factor to both 18 and 60 and divide both numbers by that factor.  I could use 2 or 3 or 6 because both 18 and 60 is divisible by any of these numbers.  I will choose 3.  I will divide the top and bottom of 18/60 by 3 to get 6/20, now I will divide the top and bottom of that number by 2 to get 3/10

7 0
2 years ago
Read 2 more answers
In 2007, a census counted 2815 of a certain animal. This was 315 fewer than the number counted in 2006. What was the population
Irina-Kira [14]

Answer: 3,130

Step-by-step explanation: 2,815 + 315 = 3,130

7 0
3 years ago
I am stuck on |x+3|<5. Can someone help?
NeTakaya
the answer would be -8<x<2
5 0
3 years ago
an elephant eats about 2500 pounds of food in 10 days. About how muck food does an elephant eat in 1000 days
andriy [413]
2500/10=250
250 represents how much the elephant can eat in one day. Since they want to know how much the elephant can eat in 1000 days you would multiply 250 and 1000 which leaves you with 250,000 pounds of food.

The elephant can eat 250,000 pounds of food in 10 days. :)
3 0
4 years ago
Get the general term for the sequence being your t3 = 11 and the t20 = 244.2
marusya05 [52]

Answer:

nth term = t_{n} = 7.639(1.2)^{n - 1}

Step-by-step explanation:

Let us assume that the given sequence is a G.P.

Now, if the first term of the G.P. is a and the common ratio is r, then

Third term = t_{3} = ar^{2} = 11 .......... (1) and  

20th term = t_{20} = ar^{19} = 244.2 ........... (2)

Now, dividing equation (2) with equation (1) we get

\frac{ar^{19} }{ar^{2} } = \frac{244.2}{11} = 22.2

⇒ r^{17} = 22.2

⇒ r = 1.2.

Hence, from equation (1) we get

a(1.2)² = 11

⇒ a = 7.639 (Approx.)

Therefore, the general term of the sequence i.e. nth term = t_{n} = 7.639(1.2)^{n - 1} (Answer)

5 0
3 years ago
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