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2 years ago

The total cost of an order of shirts from a company consists of

Mathematics

1 answer:

Luba_88 [7]2 years ago

4 0

Answer:

The cost of each shirt is the same regardless of how many shirts are ordered. The company provides the following examples to customers to help them ... Using only this information, determine the cost of ordering 200 shirts. Also ... a shirt company charges a one-time setup fee plus a certain price per shirt.

Step-by-step explanation:

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mary had $115 to spend on clothes. she found a pair of shoes for $55 and then pants for $15 each. how many pairs of pants can sh

slega [8]

Answer:

She can buy 4 pairs of pants.

6 0

3 years ago

Read 2 more answers

Ans please quickly & correctly question in the photo

LUCKY_DIMON [66]

Answer:

A Standard Drink

Step-by-step explanation:

1/3 = 0.33

1 is 33% of 3 bigger than any other one.

3 0

3 years ago

Nancy and Mark commute to work, traveling in opposite directions. Nancy leaves the house at 7:00 A.M. And average 20 miles per h

vladimir2022 [97]

Answer:

They will be 170 miles apart at 10 AM

Step-by-step explanation:

Nancy has 15´ of head start which is 1/4 hr.

NHD = 20*(1/4) = 5 miles is her head start

Mark leaves at 7.15hs = starting point

Marks stop at when they are 170 miles apart = t

------------------------------

t = the time they are 170 miles apart

d= distance in miles Nancy travels in time t

170 - (d+5) = distance in miles Mark travels in time t

------------------------------

Nancy's equation:

(1) d = 20t

Mark's equation:

(2) 170 - (d+5) = 40t

---------------------------

(2) 170-d-5=40t

(2) d+40t=165

Substitute (1) into (2)

(2) 20t+40t=165

(2) 60t=165

(2) t=2.75

7:15 AM + 2.75 hrs (2:45hs) = 10 AM

They are 170 miles apart at 10 AM

check:

(1) d=20t

(1) d=20*2.75

(1) d= 55

---------------

(2) 170 - (d+5) = 40t

(2) 170 - (d+5) = 40*2.75

(2) 170 - d-5 = 110

(2) d=55

4 0

3 years ago

6. Which is the solution to the system of equations

grin007 [14]

Answer:

Lets solve using elimination method

(x+y=-7)*-2

3x+2y=-17

-2x-2y=14

3x+2y=-17

x=-3

so lets substitute now

-3+y=-7

y=-7+3

y=-4

answer = (-3,-4)

mark me brainliest

HOPE IT HELPS :)

3 0

3 years ago

A magician’s stage has a rectangle trapdoor which is (x+ 1/2) by 2x ft. The outside rectangle length is (x+ 16) ft.

Katen [24]

Answer:

Part A:- $x +11 ft$ Part B:- $(4x+54)ft$ part C:- $x= 2ft$

Part D:- Yes it satisfy his requirement

Step-by-step explanation:

Given that,

length and breadth of Trapdoor are $(x+ \frac{1}{2} ) by 2x$ ft.

The Outside length of Rectangle is $(x+16 )$ ft.

Part A:- Total area (in square feet) of the stage can be represented by

$x^{2} + 27x+ 176$ . Write an expression for the width of stage.

So, Area of rectangle = $length \times breadth$

$x^{2} + 27x+ 176 = (x+16) \times breadth$

$Breadth = \frac{x^{2} + 27x+ 176}{x+16}$

$Breadth = x+11$ ft. ................(1)

Part B:- Write an expression for the Perimeter of the stage.

Here, Perimeter of Rectangle = $2(L+B)$

= $2(x+16 + x +11)$

= $(4x + 54) ft$

Part C:- The area of trapdoor is $10 ft^{2}$ . Find the value of x.

So, Area of trapdoor = $10 ft^{2}$

$(x +\frac{1}{2}) \times 2x =10 ft^{2}$

$2x^{2} +x - 10 = 0$

$x = \frac{-1-9}{4}$ , $\frac{-1+9}{4}$

$x = \frac{-5}{2}$ , $2$

Hence value of x is $2 ft$ (Neglecting the negative value because

length cannot be negative).

Part D:- The magician wishes to have the area of the stage be at least 20 times the area of the trapdoor. Does this stage satisfy his requirement? Explain.

So, Length of trapdoor is $(2+\frac{1}{2} ) = \frac{5}{2} ft$