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2 years ago

Anyone English here???

Mathematics

1 answer:

Luden [163]2 years ago

5 0

Yes I’m English hahahah lol

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How many outcomes are in the sample space when rolling a standard number cube and spinning a spinner with 4 equal sections?

djyliett [7]

Answer:

There are 24 outcomes in the sample space.

Step-by-step explanation:

Suppose that we have some events, such that each one of these events has a given number of outcomes.

If we have an experiment where we perform all of these events, the total number of possible outcomes is equal to the product between the number of outcomes for each one of the events.

Let's apply this to our case.

Here we have two events:

Rolling a standard number cube: 6 outcomes

Spinning a spinner with 4 equal sections: there are 4 outcomes.

Then the total number of outcomes in the sample space is the product:

C = 6*4 = 24 outcomes.

There are 24 outcomes in the sample space.

4 0

2 years ago

What is the slope of -5,5 and 8,5

arsen [322]

Answer:

hgfhgh

Step-by-step explanation:

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3 years ago

Read 2 more answers

Multiply the polynomial (3x^2+3x+5)(6x+4)

OLga [1]

Answer:

18x³+30x²+42x+20

8 0

3 years ago

Read 2 more answers

you and your sister have a combined age of 63 years your sister is 7 more than double your age. what are each of your ages

grin007 [14]

Answer:

your sister is 43 and your are 18

Step-by-step explanation:

8 0

3 years ago

According to the National Center for Health Statistics, in 1990, 28 % of babies in the United States were born to parents who

AfilCa [17]

Answer:

76 % of babies will be born out of wedlock in the $81^{st}$ year

Step-by-step explanation:

Given: In 1990, 28 % of babies in the United States were born to parents who were not married. This increased by approximately 0.6 % per year.

To find: year when 76 % of babies born out of wedlock

Solution:

A sequence is said to be in arithmetic progression if the difference between the terms is same.

For a sequence with first term as 'a' and common difference as 'd', the nth term is given by $a_n=a+(n-1)d$

The given situation also forms an arithmetic progression with $a=28\,,\,d=0.6$

Also, put $a_n=76$

So,

$a_n=a+(n-1)d\\76=28+(n-1)(0.6)\\76-28=0.6(n-1)\\48=0.6(n-1)\\\frac{48}{0.6}=n-1\\\\80=n-1\\n=80+1\\n=81$

So, 76 % of babies will be born out of wedlock in the $81^{st}$ year

6 0

3 years ago