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3 years ago

Solve the systems of equations by the elimination method: -2x + 2y = 2 -4y - 2x = -22

Mathematics

1 answer:

bekas [8.4K]3 years ago

7 0

Answer:

(3,4)

Step by step explanation:

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Can somebody help me out please

Rasek [7]

Answer:

Brainly's honor code doesn't allow quiz questions to be posted.

"Students are never allowed 2 post questions directly from tests, quizzes, and assessments, or copy answers found on Brainly during tests, quizzes, and assessments."

3 0

2 years ago

The half-life of a radioactive kind of iodine is 60 days. How much will be left after 240 days, if you start with 480 grams of i

exis [7]

Answer:

30 grams

Step-by-step explanation:

half life is 60 days so every 60 days the amount 480 grams will be half

in 240 days will decay 240 /60 = 4 times

once 480 /2 = 240

twice 240 /2 = 120

trice 120 / 2 = 60

four times 60/2 = 30 grams will be left

6 0

2 years ago

The top base of a trapezoid is 18 inches and the bottom base is 22 inches. The height of the trapezoid is 8.5 inches. What is th

kodGreya [7K]

The answer is 170. First you add base one and base two divide by twi the multiply that by the height. 18+22=40 40/2=20 20•8.5=170

7 0

2 years ago

g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds

dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

The number of ways of selecting 3 cards from 13 clubs is:

${13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286$

The number of ways of selecting 5 cards from 13 diamonds is:

${13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287$

The number of ways of selecting 0 cards from 13 spades is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

Compute the number of ways to select 5 diamonds and 3 clubs as:

${13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082$

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0

2 years ago

2918+49<br> Which numbers should be used?<br><br> The estimated quotient is?

NNADVOKAT [17]

Answer: Use all numbers to add.

2918+49=2967

Estimated.... 2918+49 ≈ 3050

Hope this helps you out.

6 0

2 years ago

Read 2 more answers