Answer:
the mean is 35.9
but if rounded it would be 40
Step-by-step explanation:
Answer:
patroon-a person given land and granted certain manorial privileges under the former Dutch governments of New York and New Jersey.
a patroon was a landholder with manorial rights to large tracts of land in the 17th-century Dutch colony of New Netherland on the east coast of North America.
a proprietary colony-A proprietary colony was a type of English colony mostly in North America and in the Caribbean in the 17th century. In the British Empire, all land belonged to the monarch, and it was his/her prerogative to divide.
Quakers-are members of a group with Christian roots that began in England in the 1650s. The formal title of the movement is the Society of Friends of the Religious Society of Friends. There are about 210,000 Quakers across the world. In Britain, there are 17,000 Quakers, and 400 Quaker meetings for worship each week.
Quakers, also called Friends, belong to a historically Christian denomination known formally as the Religious Society of Friends or Friends Church.
the frame of governing-was a proto-constitution for the Province of Pennsylvania, a proprietary colony granted to William Penn by Charles II of England. The Frame of Government has lasting historical importance as an important step in the development of American and world democracy.
holy experiment-was an attempt by the Religious Society of Friends, also known as Quakers, to establish a community for themselves and other persecuted religious minorities in what would become the modern state of Pennsylvania.
B ok ok sksk!!!!!!! Ok bye
L= R x angle = 7 x 2 = 14
Answer:
0.375 feet-lb
Step-by-step explanation:
We have been given that the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb. We are asked to find the work needed to stretch the spring 6 in. beyond its natural length.
We can represent our given information as:
We will use Hooke's Law to solve our given problem.
Substituting this value in our integral, we will get:
Using power rule, we will get:
![6=\left[ \frac{kx^2}{2} \right ]^2_0](https://tex.z-dn.net/?f=6%3D%5Cleft%5B%20%5Cfrac%7Bkx%5E2%7D%7B2%7D%20%5Cright%20%5D%5E2_0)
We know that 6 inches is equal to 0.5 feet.
Work needed to stretch it beyond 6 inches beyond its natural length would be 
Using power rule, we will get:
![\int\limits^{0.5}_0 {3x} \, dx = \left [\frac{3x^2}{2}\right]^{0.5}_0](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B0.5%7D_0%20%7B3x%7D%20%5C%2C%20dx%20%3D%20%5Cleft%20%5B%5Cfrac%7B3x%5E2%7D%7B2%7D%5Cright%5D%5E%7B0.5%7D_0)
Therefore, 0.375 feet-lb work is needed to stretch it 6 in. beyond its natural length.
