Question

What are the zeros of f(x)=(x-3)(x+8) ? Select all that apply.

Answer 1

Answer:

A) x = -8

B) x = 3

Step-by-step explanation:

This quadratic is already factored so all we have to do is solve for the zeroes. We can separate the two factors of the quadratic into x-3=0 and x+8=0. Solve for x in both of the equations and we get the zeroes as x = 3 and x = -8.

Answer 2

Answer:

3 and -8 are the zeroes of polynomial.

Option A and D are correct.

Step-by-step explanation:

Given the polynomial

$f(x)=(x-3)(x+8)$

we have to find the zeroes of the above polynomial.

Zeroes of polynomial are those values which makes the value of polynomial 0 when substituted.

∴ to find the zeroes we have to substitute the polynomial equals to 0

$f(x)=(x-3)(x+8)=0$

which implies

$x-3=0, x+8=0$

$x=3, x=-8$

Hence, 3 and -8 are the zeroes of polynomial.

Option A and D are correct.