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drek231 [11]
3 years ago
12

What did nicolaus copernicus discover about the universe

Physics
1 answer:
Keith_Richards [23]3 years ago
8 0

Answer:

Copernicus discoveres thr heliocentric theory. It was previously believed that everything orbited the Earth, geocentric theory. Copernicus said he believed the Earth and everything else orbited around the Sun.

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A wattage rating of a lightbulb is the power it consumers when it is connected across a 120 V potential difference. How does the
navik [9.2K]

Answer:

The answer is C.

120 V with 60 W light bulb is 240 ohms.

120 V with 100 W light bulb is 144 ohms.

The 100 W bulb has less resistance :)

7 0
3 years ago
There are 3.3V passing through an orange power supply cable, and there are 0.025 ohms of resistance in the orange wire. How much
PIT_PIT [208]
P = V^2 / R.

So, 3.3^2 / 0.025 = 435.6W.

Note, you can get the power equation from:
P = V*I. Also, I = V/R.
Substituting V/R in for I in the 1st equation, you get P = V^2 / R.
5 0
3 years ago
What is the speed of a commercial jet which travels form New York to Los Angeles (4800) in 6 hours
Colt1911 [192]

Answer:

Speed = 800km}/hr

Explanation:

Given

Distance = 4800km

Time = 6hr

Required

Determine the speed of the jet

The speed is calculated as:

Speed = \frac{Distance}{Time}

Substitute 4800 km for Distance and 6hr for Time

Speed = \frac{4800km}{6hr}

Speed = 800km}/hr

<em>Hence, the speed of the commercial jet is 800km/hr</em>

8 0
3 years ago
According to Bohr's model of the hydrogen atom, the atomic orbit with a quantum number of n = 1 has
8_murik_8 [283]
The answer will be b but check it by yourself we are humans
5 0
3 years ago
A 12.0-g sample of carbon from living matter decays at the rate of 162.5 decays/minute due to the radioactive 14C in it. What wi
Ghella [55]

Answer:

a)143.8 decays/minute

b)0.41 decays/minute

Explanation:

From;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/2=half-life of C-14= 5670 years

t= time taken to decay

Ao= activity of a living sample

A= activity of the sample under study

a)

0.693/5670 = 2.303/1000 log(162.5/A)

1.22×10^-4 = 2.303×10^-3 log(162.5/A)

1.22×10^-4/2.303×10^-3 = log(162.5/A)

0.53 × 10^-1 = log(162.5/A)

5.3 × 10^-2 = log(162.5/A)

162.5/A = Antilog (5.3 × 10^-2 )

A= 162.5/1.13

A= 143.8 decays/minute

b)

0.693/5670 = 2.303/50000 log(162.5/A)

1.22×10^-4 = 4.61×10^-5 log(162.5/A)

1.22×10^-4/4.61×10^-5 = log(162.5/A)

0.26 × 10^1 = log(162.5/A)

2.6= log(162.5/A)

162.5/A = Antilog (2.6 )

A= 162.5/398.1

A= 0.41 decays/minute

4 0
3 years ago
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