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Natasha2012 [34]
3 years ago
5

A wheel with radius 0.487 m rotates 5.75 times every second. find the period of this motion.

Physics
1 answer:
marin [14]3 years ago
3 0
Calculate the circumference of the circular path of the wheel by the equation,
    C = 2πr
where C is the circumference,
           r is the radius

Substituting the known values,
    C = 2(π)(0.487 m) = 3.06 m

Then, period of the motion will be determined by dividing the number of rotations done,
 
     T = (3.06 m) / (5.75 /s) = 0.53 s

<em>ANSWER: 0.53 s</em>
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A box of mass 14 kg sits on an inclined surface with an angle of 52degrees. What is the component of the weight of the box along
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First, we calculate for the weight of the object by multiplying the given mass by the acceleration due to gravity which is equal to 9.8 m/s²
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The component of the weight that is along the surface of the inclined plane is equal to this weight times the sine of the given angle. 
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5 0
3 years ago
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diamong [38]

ANSWER:

IV, Type of dish detergent. DV, height of foam. CV, type of container, amount of water in container, temperature of water, time the container is agitated.

Explanation:

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Constant variables(CV)- things that do not change in order to isolate the tested variables as much as possible.

3 0
3 years ago
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denpristay [2]

Answer:

hi, this is the answer

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The object is stationary. ...

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pls mark this as the brainliest...

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There are some evidence for big bang as :

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