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Natasha2012 [34]
3 years ago
5

A wheel with radius 0.487 m rotates 5.75 times every second. find the period of this motion.

Physics
1 answer:
marin [14]3 years ago
3 0
Calculate the circumference of the circular path of the wheel by the equation,
    C = 2πr
where C is the circumference,
           r is the radius

Substituting the known values,
    C = 2(π)(0.487 m) = 3.06 m

Then, period of the motion will be determined by dividing the number of rotations done,
 
     T = (3.06 m) / (5.75 /s) = 0.53 s

<em>ANSWER: 0.53 s</em>
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