A wheel with radius 0.487 m rotates 5.75 times every second. find the period of this motion.

1 answer:

3 0

Calculate the circumference of the circular path of the wheel by the equation,
C = 2πr
where C is the circumference,
r is the radius

Substituting the known values,
C = 2(π)(0.487 m) = 3.06 m

Then, period of the motion will be determined by dividing the number of rotations done,

T = (3.06 m) / (5.75 /s) = 0.53 s

ANSWER: 0.53 s

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