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Natasha2012 [34]
3 years ago
5

A wheel with radius 0.487 m rotates 5.75 times every second. find the period of this motion.

Physics
1 answer:
marin [14]3 years ago
3 0
Calculate the circumference of the circular path of the wheel by the equation,
    C = 2πr
where C is the circumference,
           r is the radius

Substituting the known values,
    C = 2(π)(0.487 m) = 3.06 m

Then, period of the motion will be determined by dividing the number of rotations done,
 
     T = (3.06 m) / (5.75 /s) = 0.53 s

<em>ANSWER: 0.53 s</em>
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A lawn roller is rolled across a lawn by a force of 107 N along the direction of the handle, which is 13.5 ◦ above the horizonta
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Answer:

22.02 m

Explanation:

given,

Force, F = 107 N

angle made with horizontal = 13.5◦

Power develop by the lawn roller = 69.4 W

time = 33 s

distance = ?

Force along horizontal= F cos θ

          = 107 cos 13.5°= 104 N

Power = \dfrac{work\ done}{time}

69.4 = \dfrac{W}{33}

W = 2290.2 J

Work done= Force x displacement

displacement= \dfrac{2290.2}{104}

                      = 22.02 m

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3 years ago
Help please!!! 100 points
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3 years ago
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What type of reaction feels cold to the touch?
IRISSAK [1]

Answer:

Explanation:

An endothermic reaction absorbs heat, so it will be cold to touch.

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3 years ago
Question 30
stellarik [79]

Answer: 0.69\°

Explanation:

The angular diameter \delta of a spherical object is given by the following formula:

\delta=2 sin^{-1}(\frac{d}{2D})

Where:

d=16 m is the actual diameter

D=1338 m is the distance to the spherical object

Hence:

\delta=2 sin^{-1}(\frac{16 m}{2(1338 m)})

\delta=0.685\° \approx 0.69\° This is the angular diameter

3 0
3 years ago
A 19.0-kg cart is moving with a velocity of 7.20 m/s down a level hallway. A constant force of -13.0 N acts on the cart and its
gulaghasi [49]

Answer:

a. -369.36J

b. -123.9J

c. 9.52m

Explanation:

From the expression for kinetic energy

K. E=1/2mv^2

Since the mass is constant, but the velocity changes. Hence the change in kinetic energy is

K.E=1/2*19(3.6²-7.2²)

K.E= -369.36J

b. to determine the workdone by the force,we determine the distance moved.

But the acceleration is from

F=ma ,

a=f/m

a=-13/19

0.68m/s²

the distance moved is

s=v²/2a

s=3.6²/2*0.68

s=9.52m

Hence the work done is

W=force * distance

W=-13*9.52

W=-123.9J

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s=v²/2a

s=3.6²/2*0.68

s=9.52m

4 0
4 years ago
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