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3 years ago

What expression is equivalent to – 6( – 6g–4)–2g?

Mathematics

1 answer:

allsm [11]3 years ago

6 0

Answer:

(36g+24)-2g.

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1. Which point on the number line

ss7ja [257]

Answer:

d) Point D

Step-by-step explanation:

$\sqrt{62} = 7.87400787$

8 0

3 years ago

X-2y+z=5 <br>3x+3y-2z=-6 <br>2x-y+3z=11 <br>find x+y+z

BartSMP [9]

x - 2y + z = 5 | *2
⇒ 2x - 4y+ 2z=10
3x + 3y - 2z = - 6 } I sum up these relations
--------------------------------
2x+3x - 4y+3y+2z-2z=10-6
5x - y = 4 (1)

3x + 3y - 2z = - 6 | *3 ⇒ 9x + 9y - 6z = - 18
2x - y + 3z = 11 | *2 ⇒ 4x - 2y + 6z= 22 I sum up these
----------------------------------
⇒ 9x+4x+9y-2y-6z+6z= 4
13x+ 7y= 4 (2)
I write (1) and (2)
5x - y = 4 | *7
35x - 7y= 28
13x+7y=4
48x = 32
x= 32/48=4/6 ( 32:8=4, 48:8=6)
x= 2/3
5x-y=4,
5*2/3-y=4
y=10/3 -4=10/3-12/3=-2/3
⇒ y= - 2/3
x - 2y + z = 5
2/3 - 2*(-2/3)+z=5
2/3+4/3+z=5
6/3+z=5
2+z=5
z=3
x+y+z=2/3-2/3+3=3

x+y+z=3

3 0

3 years ago

In geometry, Heron's formula (sometimes called Hero's formula), named after Hero of Alexandria, gives the area of a triangle by

uysha [10]

Answer:

C) $6.495\: ft^2$

Step-by-step explanation:

a = 7 ft, b = 3 ft, c = 5 ft (Given)

Therefore, a + b + c = 7 + 3 + 5 = 15 ft

Let's calculate semi Perimeter of the triangle which is given by s

$s =\frac{a+b+c}{2}=\frac{15}{2} = 7.5 \: ft$

Now, by Heron's formula, area of triangle ABC is given as:

$A(\triangle ABC) =\sqrt{s(s-a) (s-b)(s-c)}$

$\therefore A(\triangle ABC) =\sqrt{7.5(7.5-7) (7.5-3)(7.5-5)}$

$\therefore A(\triangle ABC) =\sqrt{7.5(0.5) (4.5)(2.5)}$

$\therefore A(\triangle ABC) =\sqrt{42.1875}$

$\therefore A(\triangle ABC) =6.49519053$

$\therefore A(\triangle ABC) =6.495\: ft^2$

8 0

3 years ago

Two positive integers have a sum of 10 and a product of 21. What are the integers?

lara [203]

Answer:

Step-by-step explanation:

$x,y-\text{positive integers}\\\\\text{The system of equations:}\\\\\left\{\begin{array}{ccc}x+y=10&\text{subtract}\ y\ \text{from both sides}\\xy=21\end{array}\right\\\\\left\{\begin{array}{ccc}x=10-y&(1)\\xy=21&(2)\end{array}\right\\\\\text{substitute (1) to (2):}\\\\(10-y)(y)=21\qquad\text{use the distributive property}\ a(b-c)=ab-ac\\\\10y-y^2=21\qquad\text{subtract 21 from both sides}\\\\-y^2+10y-21=0\qquad\text{change the signs}\\\\y^2-10y+21=0\\\\y^2-3y-7y+21=0\\\\y(y-3)-7(y-3)=0$

$(y-3)(y-7)=0\iff y-3=0\ \vee\ y-7=0\\\\y-3=0\qquad\text{add 3 to both sides}\\\\y=3\\\\y-7=0\qquad\text{add 7 to both sides}\\\\y=7\\\\\text{Put the value of}\ y\ \text{to (1):}\\\\x=10-3=7\ or\ x=10-7=3$

7 0

3 years ago

Use the Binomial Theorem to expand the binomial<br> (d + 5b)3

Gekata [30.6K]

Answer:

3×d+5b×3

=3d+15b.

I think it will help you.

5 0

3 years ago